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Fynjy0 [20]
3 years ago
8

What is 2?8,644~200,000 in equation

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0
Divided the problem to get the answer
You might be interested in
Resultado de ____ · 200 = -1.000
elixir [45]

Answer:

-1.000/200 = 5

(-5) · 200 = -1.000

6 0
3 years ago
3. Could a 5 x 8 matrix have dim Col A 6 and dim Nul A - 2? Justify your answer. (Hint: Think about the possible pivot rows and
alexdok [17]

Answer:

No

Step-by-step explanation:

A 5x8 matrix A represents a linear transformation between the vector space \mathbb{R}^8 and \mathbb{R}^5. Remeber that the columns of A generate the image of the linear transformation, which is a vector subspace of \mathbb{R}^5. Therefore, \dim \text{Col}A \leq 5, which is the dimension of the the total space.

4 0
4 years ago
The dot plots below show the age of some dance students and some yoga students: Two dot plots are shown one below the other. The
11Alexandr11 [23.1K]

Answer:

The yoga students

Step-by-step explanation:

This one is kinda easy but i took the test and got it right have a good day! :)

7 0
3 years ago
Read 2 more answers
The average weight of a particular box of crackers is 28.0 ounces with a standard deviation of 0.9 ounce. The weights of the box
Juliette [100K]

Answer:

a. 97.72%

Step-by-step explanation:

The weights of boxes follows normal distribution with mean=28 ounce and standard deviation=0.9 ounces.

a. We have to calculated the percentage of the boxes that weighs more than 26.2 ounces.

Let X be the weight of boxes. We have to find P(X>26.2).

The given mean and Standard deviations are μ=28 and σ=0.9.

P(X>26.2)= P((X-μ/σ )> (26.2-28)/0.9)

P(X>26.2)= P(z> (-1.8/0.9))

P(X>26.2)= P(z>-2)

P(X>26.2)= P(0<z<∞)+P(-2<z<0)

P(-2<z<0) is computed by looking 2.00 in table of areas under the unit normal curve.

P(X>26.2)=0.5+0.4772

P(X>26.2)= 0.9772

Thus, the percent of the boxes weigh more than 26.2 ounces is 97.72%

5 0
3 years ago
Which one is correct?
nordsb [41]

Answer:

SSS or SAS

Step-by-step explanation:

Remark

Since the two diagonals bisect each other, you have created two sets of equal lines. If that is the case, then you could prove the equality of the triangles 2 different ways.

1) The angles at the center are vertically angles which makes them equal. Since they are equal, the triangles are congruent by SAS. Notice that the angle is between the 2 equal sides.

2) Since CD and AB are marked as being equal, the triangles are congurent by SSS.

6 0
3 years ago
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