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2 years ago

8

What is 2?8,644~200,000 in equation

1 answer:

IgorLugansk [536]2 years ago

5 0

Divided the problem to get the answer

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Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

3 years ago

What kind of numbers are in the descending pattern?

Olin [163]

Its when you range the numbers greatest to least like for example 27,21,116,13,9

3 0

3 years ago

What's 30.08 divided by 4

belka [17]

30.08 divided by 4 is 7.52

6 0

2 years ago

Read 2 more answers

An IPod Nano has 2 gigabytes of storage and can hold about 500 songs. The iPod Plus has 80 gigabytes of storage. How many songs

jasenka [17]

80 * 250 =20,000

The iPod can hold 250 songs per gigabyte.

4 0

3 years ago

Read 2 more answers

Please view the attachment.

quester [9]

-1 * (-4) = 4; 3 * (-4) = -12; 6 * (-4) = -24; -3 * (-4) = 12

7 0

3 years ago