The right answer is N2(g) + 3H2(g) => 2NH3(g).
Ammonia (NH3) is produced by the synthesis of nitrogen (N2) and hydrogen (H2):
N2 + 3 H2 → 2 NH3
During the first half of the 20th century, the NH3-green was produced without CO2 emission at
from hydroelectricity, water, and atmospheric air.
H2 came from the electrolysis of water, the N2 of atmospheric air.
The final volume of the unknown gas is 787.5 ml
Given:
volume of unknown gas = 450.0 mL
initial pressure of unknown gas = 0.07 atm
final pressure of unknown gas = 0.04 atm
To Find:
final volume of the unknown gas
Solution:
Substituting these values into Boyle’s law, we get
P1V1 = P2V2
(0.07)(450) = (0.04)V2
V2 = (0.07)(450)/(0.04)
V2 = 787.5
So, final volume of the unknown gas is 787.5 ml
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Answer:
Single Covalent Bond = 2 Electrons
Double Covalent bond = 4 Electrons
Triple Covalent Bond =3 Pairs of electrons
Explanation:
Explanation:
What are the mole ratio and the mass ratio for H2O to O2 in the reaction 2H2 + O2 → 2H2O? Mole ratio of H2O to O2 in the given reaction is H2O : O2 = 2 : 1. Mass ratio of H2O to O2 in the given reaction is H2O : O2 = 36 : 32 = 1 : 1.1.
The halogens (VIIA elements) all have seven valence electrons. All the halogens gain a single electron to fill their valence energy level. And all of them form an anion with a single negative charge.
