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OleMash [197]
2 years ago
11

450.0 mL of an unknown gas has its pressure decreased from 0.07 atm to 0.04 atm. Assuming temperature remains constant, what wou

ld be the final volume of the unknown gas
Chemistry
1 answer:
tino4ka555 [31]2 years ago
4 0

The final volume of the unknown gas is 787.5 ml

Given:

volume of unknown gas = 450.0 mL

initial pressure of unknown gas = 0.07 atm

final pressure of unknown gas = 0.04 atm

To Find:

final volume of the unknown gas

Solution:

Substituting these values into Boyle’s law, we get

P1V1 = P2V2

(0.07)(450) = (0.04)V2

V2 = (0.07)(450)/(0.04)

V2 = 787.5

So, final volume of the unknown gas is 787.5 ml

Learn more about Volume here:

brainly.com/question/25736513

#SPJ4

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Liono4ka [1.6K]

The mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

<h3>Calculating mass </h3>

From the question we are to calculate the mass of NaHCO₃ (sodium bicarbonate) used in the experiment

From the given information

Mass of empty evaporating dish = 46.233g

Mass of evaporating dish + Sodium bicarbonate = 48.230g

∴ Mass of sodium bicarbonate (NaHCO₃) = [Mass of evaporating dish + Sodium bicarbonate] - [Mass of empty evaporating dish]

Mass of sodium bicarbonate (NaHCO₃) = 48.230g - 46.233g

Mass of sodium bicarbonate (NaHCO₃) = 1.997 g

Hence, the mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g

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