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2 years ago

5

PLEASE HELP I HAVE SOME POINTS THAT I'M GIVING OUT IF YOU ANSWER THIS QUESTION CORRECTLY. PLEASE HELP For each value of x , dete

rmine whether it is a solution to 38 >/ 29 + x .
8: yes or no
14: yes or no
6: yes or no
9: yes or no

1 answer:

Zigmanuir [339]2 years ago

3 0

Answer:

8: yes

14: no

6: yes

9: yes

Step-by-step explanation:

Hope this helps!

(P.S.I changed the answer)

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Show all work please will give brainliest answer❕❗️❕❗️❕❗️❕❗️❕David drops a ball from a bridge at an initial height of 100 meters

Inessa [10]

First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.

Tell me if you need any clarification

PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds

Tell me if you need any clarification

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2 years ago

Which numbers represent the lower quartile, the median, and the upper quartile of the following set of numbers?

kotegsom [21]

Answer:

Lower quartile: 85; median: 97; upper quartile 115.5

Step-by-step explanation:

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2 years ago

How do you find the value of x and the length of the indicated segment

kaheart [24]

You have to multiply

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2 years ago

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$

Thus the coordinates of B are:

$B=(-1+\frac{2\sqrt{3} }{3},2)$

Now this point B lies on the parabola, and therefore it must satisfy the equation $y=a(x+1)(x-5).$

Thus

$2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)$

Therefore

$a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}$

$\boxed{a=-0.3575}$

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2 years ago

While playing a trivia game Adam answer eight questions correct in the first half and two questions correct in the second half i

ratelena [41]

Answer:

80 points

Step-by-step explanation:

First Half: Second Half: Total Right Answers

8 questions right + 2 questions right = 10 questions right

10*8 points a piece = 80 points

3 0

2 years ago