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expeople1 [14]
3 years ago
11

Sodium benzoate, the sodium salt of benzoic acid, is used as a food preservative. A sample containing solid sodium benzoate mixe

d with sodium chloride is dissolved in 50.0 mL of .5 M HCl, giving an acidic solution (benzoic acid mixed with HCl ). This mixture is then titrated with .393 M NaOH. After the addition of 46.50 mL of the solution, the pH is found to be 8.2. At this point, the addition of one more drop ( .02 mL) of NaOH raises the pH to 9.3 . Calculate the mass of sodium benzoate (NaC6H5COO) in the original sample. (Hint: At the equivalence point, the total number of moles of acid [here HCl] equals the total number of moles of base [here, both NaOH and NaC6H5COO]
Chemistry
1 answer:
GalinKa [24]3 years ago
3 0

Answer:

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Explanation:

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write the spontaneous net cell reaction. include physical states. net cell reaction: 2al(s) 2br {2}(l)
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8 0
1 year ago
How to know if something is actually white gold?
Alla [95]
White gold is made out of yellow gold mixed with other metals, which are added to make the alloy harder and whiter.
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4 0
2 years ago
What is the volume, in liters, of 576 grams of so2 gas at stp?
katen-ka-za [31]
The volume  in  liters  of  576 grams  of SO2  gas  at STP  is   calculated as below

calculate the moles of SO2 = mass/molar  mass

= 576 g/64 g /mol  = 9 moles

At  STP  1mole =22.4 L
what  9 mole =? liters

by cross  multiplication

= 22.4 L x  9 moles/ 1moles = 201.6 liters
5 0
2 years ago
Calculate the pH of: (a) 0.1M HCl; (b) 0.1M NaOH; (c) 3 X 10% M HNO3; (d) 5 X 10-10 M HCIO.; and (e) 2 x 10-8 M KOH.
Shtirlitz [24]

Answer:

(a) pH = -Log (0.1M) = 1

(b) pH = -Log (10^{-13}M) = 13

(c) pH = -Log (3x10^{-3}M) = 2.5

(d) pH = -Log (4.93x10^{-10}M) = 9.3

(e) pH = -Log (5^{-7}M) = 6.3

Explanation:

To calculate de pH of an acid solution the formula is:

pH = -Log ([H^{+}]) = 1

were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.

(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.

(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:

K_{w} =[H^{+} ][OH^{-}]=10^{-14}

clearing the [H^{+} ]

[H^{+} ]=\frac{10^{-14}}{[OH^{-}]}

(d) is a weak base so it is necessary to solve the equilibrium first, knowing Ka=3.24x10^{-8}

The reaction is HClO  →  H^{+} + CO^{-} so the equilibrium is

Ka=3.24x10^{-8}=\frac{x^{2}}{5x10^{-8}-x}

clearing the <em>x</em>

{x^{2}={1.62x10^{-17}-3.24x10^{-8}x}

x=[H^{+}]=4.93x10^{-10}

6 0
3 years ago
Can invasive species affect humans?
skad [1K]

Answer:

To a certain extent absolutly. They can impact human health for the worse and more.

4 0
3 years ago
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