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777dan777 [17]
3 years ago
7

Calculate the mass of 5.3 moles of chloric acid (HClO3). Please Answer ASAP!!!! :((((((\

Chemistry
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

292.215

Explanation:

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Given the following Babnced equation 4NH3 +5O2>
igor_vitrenko [27]
4NH3 + 5O2 ==> 4NO + 6H2O Balanced equation
ALWAYS WORK IN MOLES, NOT IN GRAMS
moles of NO produced = 70.5 g NO x 1 mole/30 g = 2.35 moles NO
Since this represents only a 29.8% yield, find what 100% yield would be:
2.35 moles/0.298 = 7.89 moles of NO
From the balanced equation 4 moles NH3 produces 4 moles of NO. Calculate moles of NH3 needed:
7.89 moles NO x 4 moles NH3/4 moles NO = 7.89 moles NH3 needed
Find grams of NH3 needed:
7.89 moles NH3 x 17 g/mole = 134 g NH3 needed
8 0
2 years ago
What is the basic of an organic molecule
Deffense [45]
Organic molecules<span> are the </span>molecules<span> of life and are built around chains of carbon atoms that are often quite long. There are four main groups of </span>organic molecules<span>that combine to build cells and their parts: carbohydrates, proteins, lipids, and nucleic acids.</span><span>What is the basic of an organic molecule

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4 0
3 years ago
Read 2 more answers
Describe the type and nature of the bonding that occurs between reactive metals and nonmetals.
Bingel [31]
It’s ionic bond based on electrons gain/loss.
7 0
3 years ago
Why are most organic compounds nonconducting and insoluble in water?
maksim [4K]
I think the correct answers from the choices listed above are the second and the last options. Organic compounds are nonducting and insoluble in water because of the bonds that these compounds contain. Most organic compounds don't dissolve in water because they are nonpolar. They don't conduct electricity because they are covalent, not ionic.
4 0
3 years ago
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How many liters of space will 7.80 moles of methane gas (CH4) occupy at STP
Alchen [17]

Answer:

V CH4(g) = 190.6 L

Explanation:

assuming ideal gas:

  • PV = RTn

∴ STP: T =298 K and P = 1 atm

∴ R = 0.082 atm.L/K.mol

∴ moles (n) = 7.80 mol CH4(g)

∴ Volume CH4(g) = ?

⇒ V = RTn/P

⇒ V CH4(g) = ((0.082 atm.L/K.mol)×(298 K)×(7.80 mol)) / (1 atm)

⇒ V CH4(g) = 190.6 L

4 0
3 years ago
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