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vichka [17]
3 years ago
12

how many kilograms of water must evaporate from 8kg of a 25% salt solution to produce 40% salt solution?

Chemistry
1 answer:
Lena [83]3 years ago
6 0

Answer: The kilograms of water must evaporate from 8kg of a 25% salt solution to produce 40% salt solution is 3 kg.

Explanation:

According to the ratio and proportion:

C_1m_1=C_2m_2

where,

C_1 = concentration of ist solution = 25%

m_1 = mass of ist solution = 8 kg

C_2 = concentration of second solution = 40%

m_2 = mass of second solution = ? kg

25\times 8=40\times m_2

m_2=5kg

Thus the final solution must have a mass of 5 kg , i.e (8-5)= 3 kg of mass must be evaporated.

Therefore, the mass that must be evaporated from 8kg of a 25% salt solution to produce 40% salt solution is 3 kg.

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Answer:

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Explanation:

Data Given

initial volume V1 = 4.50 gallons

convert volume from gallons to L

                               1 gallon = 3.78541 L

                               4. 50 gallon = 3.785 L x 4.50

So,                        

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final Volume V2 = ?

initial Temperature T1  = 80° F

convert Temperature to Kelvin

                              T1 = ( 80° F -32) / 1.8 +273

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convert Temperature to Kelvin

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Solution:

This problem will be solved by using charles' law equation at constant pressure.

The formula used

                      V1 / T1 = V2 / T2

As we have to find out volume, so rearrange the above equation

                      V2 = V1 x T2 / T1

Put value from the data given and conversion information in above equation

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V2 =  21. 19 L

So the final volume of Methane gas = 21.19 L

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