What is the approximate volume of 19g of fluorine gas at a pressure of 4.0 atmospheres and a temperature of 127o C?
1 answer:
Answer:
V = 8.21 L
Explanation:
Given data:
Volume of fluorine = ?
Mass of fluorine = 19 g
Pressure = 4.0 atm
Temperature = 127 °C(127+ 273 =400 K)
Solution:
Number of moles of fluorine:
Number of moles = mass/molar mass
Number of moles = 19 g/ 19 g/mol
Number of moles = 1 mol
PV = nRT
V = nRT/P
V = 1 mol ×0.0821 atm. L. mol⁻¹. k⁻¹ × 400 K/ 4 atm
V = 32.84 L/ 4
V = 8.21 L
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