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zalisa [80]
2 years ago
9

Eva begins an 8 week program to improve her health. By the end of first week, she can do 10 sit-ups in a row. By the end of the

second week, she can do 15 sit-ups in a row. By the end of the third week, she can do 20 sit-ups in a row. If Eva continues at this rate, how many sit-ups can she do in a row by the end of the training program?
Mathematics
2 answers:
Pachacha [2.7K]2 years ago
8 0

Answer:

30 fine years ya know I was in England robing a back sooo

Slav-nsk [51]2 years ago
5 0

Answer:

in 8 weeks she can do 45 sit ups

Step-by-step explanation:

add 5 to each week

You might be interested in
Will give brainliest - somebody please help me
mina [271]

Answer:

1 to the left and 7 up

Step-by-step explanation:

The x coordinate goes from 3 to 2, so that is your 1 to the left.

The y coordinate goes from -4 to 3, so that is your 7 up.

3 0
3 years ago
4. Write an equation for the line that is parallel to the given line and that passes
pentagon [3]

Answer:

y=\frac{5}{2}x-14

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0)
  • Parallel lines always have the same slope

<u>1) Determine the slope (m)</u>

y=\frac{5}{2}x-10

In the given equation, \frac{5}{2} is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of \frac{5}{2}. Plug this into y=mx+b:

y=\frac{5}{2}x+b

<u>2) Determine the y-intercept (b)</u>

y=\frac{5}{2}x+b

Plug in the given point (-6,-29) and solve for b

-29=\frac{5}{2}(-6)+b

Simplify -6 and 2

-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b

Add 15 to both sides to isolate b

-29+15=-15+b+15\\-14=b

Therefore, the y-intercept is -14. Plug this back into y=\frac{5}{2}x+b:

y=\frac{5}{2}x-14

I hope this helps!

4 0
2 years ago
Reliance on solid biomass fuel for cooking and heating exposes many children from developing countries to high levels of indoor
kherson [118]

Answer:

A) 95% confidence interval for the population mean PEF for children in biomass households = (3.314, 3.486)

95% confidence interval for the population mean PEF for children in LPG households

= (4.195, 4.365)

Simultaneous confidence interval for both = (3.314, 4.365)

B) The result of the hypothesis test is significant, hence, the true average PEF is lower for children in biomass households than it is for children in LPG households.

C) 95% confidence interval for the population mean FEY for children in biomass households = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.365)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Step-by-step explanation:

A) Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the z-distribution. This is because although, there is no information provided for the population standard deviation, the sample sizes are large enough for the sample properties to approximate the population properties.

Finding the critical value from the z-tables,

z-critical value for 95% confidence level = 1.960 (from the z-tables)

For the children in the biomass households

Sample mean = 3.40

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.20

N = sample size = 756

σₓ = (1.20/√756) = 0.04364

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 3.40 ± (1.960 × 0.04364)

CI = 3.40 ± 0.08554

95% CI = (3.31446, 3.48554)

95% Confidence interval = (3.314, 3.486)

For the children in the LPG households

Sample mean = 4.28

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.19

N = sample size = 752

σₓ = (1.19/√752) = 0.043395

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 4.28 ± (1.960 × 0.043395)

CI = 4.28 ± 0.085054

95% CI = (4.1949, 4.3651)

95% Confidence interval = (4.195, 4.365)

Simultaneous confidence interval for both = (3.214, 4.375)

B) The null hypothesis usually goes against the claim we are trying to test and would be that the true average PEF for children in biomass households is not lower than that of children in LPG households.

The alternative hypothesis confirms the claim we are testing and is that the true average PEF is lower for children in biomass households than it is for children in LPG households.

Mathematically, if the true average PEF for children in biomass households is μ₁, the true average PEF for children in LPG households is μ₂ and the difference is μ = μ₁ - μ₂

The null hypothesis is

H₀: μ ≥ 0 or μ₁ ≥ μ₂

The alternative hypothesis is

Hₐ: μ < 0 or μ₁ < μ₂

Test statistic for 2 sample mean data is given as

Test statistic = (μ₂ - μ₁)/σ

σ = √[(s₂²/n₂) + (s₁²/n₁)]

μ₁ = 3.40

n₁ = 756

s₁ = 1.20

μ₂ = 4.28

n₂ = 752

s₂ = 1.19

σ = √[(1.20²/756) + (1.19²/752)] = 0.061546

z = (3.40 - 4.28) ÷ 0.061546 = -14.30

checking the tables for the p-value of this z-statistic

Significance level = 0.01

The hypothesis test uses a one-tailed condition because we're testing in only one direction.

p-value (for z = -14.30, at 0.01 significance level, with a one tailed condition) = 0.000000001

The interpretation of p-values is that

When the p-value > significance level, we fail to reject the null hypothesis and when the p-value < significance level, we reject the null hypothesis and accept the alternative hypothesis.

Significance level = 0.01

p-value = 0.000000001

0.000000001 < 0.01

Hence,

p-value < significance level

This means that we reject the null hypothesis, accept the alternative hypothesis & say that true average PEF is lower for children in biomass households than it is for children in LPG households.

C) For FEY for biomass households,

Sample mean = 2.3 L/s

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation = 0.5

N = sample size = 756

σₓ = (0.5/√756) = 0.018185

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 2.30 ± (1.960 × 0.018185)

CI = 2.30 ± 0.03564

95% CI = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.365)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Hope this Helps!!!

3 0
3 years ago
Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac
Brums [2.3K]

Answer: The population will be 408,000 people.

Step-by-step explanation:

So in 2000 there were 200,000 people and it started to grow 8% every year so up to 2013.

so find 8% of 200,000 and then multiply it by the  the number of years.

8% * 200,000 =  16,000

Find the difference between the years.

2013 - 2000 = 13 years

13 * 16000 = 208000  This is the amount of new people from 2000 to 2013 so add it to the original population.

208,000 + 200,000 = 408,000  

5 0
3 years ago
10-5 x a = 10 x (12+ 1/4a)
ki77a [65]

Answer:

I hope this is helpful wish you the luck

3 0
3 years ago
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