Answer:
a. E(x) = 3.730
b. c = 3.8475
c. 0.4308
Step-by-step explanation:
a.
Given
0 x < 3
F(x) = (x-3)/1.13, 3 < x < 4.13
1 x > 4.13
Calculating E(x)
First, we'll calculate the pdf, f(x).
f(x) is the derivative of F(x)
So, if F(x) = (x-3)/1.13
f(x) = F'(x) = 1/1.13, 3 < x < 4.13
E(x) is the integral of xf(x)
xf(x) = x * 1/1.3 = x/1.3
Integrating x/1.3
E(x) = x²/(2*1.13)
E(x) = x²/2.26 , 3 < x < 4.13
E(x) = (4.13²-3²)/2.16
E(x) = 3.730046296296296
E(x) = 3.730 (approximated)
b.
What is the value c such that P(X < c) = 0.75
First, we'll solve F(c)
F(c) = P(x<c)
F(c) = (c-3)/1.13= 0.75
c - 3 = 1.13 * 0.75
c - 3 = 0.8475
c = 3 + 0.8475
c = 3.8475
c.
What is the probability that X falls within 0.28 minutes of its mean?
Here we'll solve for
P(3.73 - 0.28 < X < 3.73 + 0.28)
= F(3.73 + 0.28) - F(3.73 + 0.28)
= 2*0.28/1.3 = 0.430769
= 0.4308 -- Approximated
Answer:
SYNTAX PROPERTY
Step-by-step explanation:
Answer:
the rate of the first cyclist: 28km/h
the rate of the 2nd cyclist 28+4= 32km/h
Step-by-step explanation:
x= the rate of the first cyclist
x+4= the rate of the 2nd cyclist
after 4 hours: + the first cyclist travels 4x (km)
+ the 2nd cyclist travels 4(x+4) (km)
because the two cyclists are 240 km apart after 4 hours
=> 4x + 4(x+4) = 240 => x= 28
i hope it's useful forr u =)))
Answer:
X= 9//
Step-by-step explanation:
abc = efg
ac + cd = eg + gh
9 + (x+2) = 6 + (2x-4)
9 - 6 = 2x-4 - (x+2)
3 = x - 6
3+6 = x
9 = x//
It is a right agn have a good day
