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Delicious77 [7]
3 years ago
5

Pounds would be a good unit to measure everything but

Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0

Answer:

B.Milk

Step-by-step explanation:

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Insert parentheses on the left side of the equation to make the statement true for all values of p
lukranit [14]
7+5(p-p)=7 
because 7+5p-5p=7
cross our the 5p because 5p-5p is 0
7=7
~JZ
Hope it helps!
3 0
3 years ago
The zeros of function dare -3 and 8. Which expression could be a factor of function d?
erastovalidia [21]

Answer:

(x + 3)

Step-by-step explanation:

Using the zero product property

x-a = 0  x-b = 0  where a and b are the zeros

(x-a)(x-b) =0

(x- -3)(x -8) =0

(x+3) (x-8) =0

3 0
3 years ago
On a game show, Elena is given the choice of three doors: Behind one door is the Grand Prize; behind the others, consolation pri
Len [333]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =
geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

L_z=9-\lambda=0

L_\lambda=x-y+z-1=0

L_\mu=x^2+y^2-1=0

L_z=0 tells us \lambda=9, so that

L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu

L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}

Then with L_\mu=0, we get

x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2

and L_\lambda=0 tells us

x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}

Then there are two critical points, \left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right). The critical point with the negative x-coordinates gives the maximum value, 9+\sqrt{185}.

8 0
3 years ago
Simon started for school at 8:30 he got there 15minuter later. what time did he get to school​
laila [671]
Simon started school at 8:45.
6 0
3 years ago
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