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Ilia_Sergeevich [38]
3 years ago
15

a pair of adjacent side of a rectangle are in the ratio 3 : 4 if its diagonal is 20 cm find the length of sides and hence the pe

rimeter of the rectangle ​
Mathematics
1 answer:
lutik1710 [3]3 years ago
7 0

Answer:

Step-by-step explanation:

Ratio=3:4

so,the pair of adjacent sides are 3x,4x

Pythagorean theorem,

(3x)^{2}+(4x)^{2}=20^{2}\\9x^{2}+16x^{2}=400\\\\25x^{2}=400\\\\x^{2}=\frac{400}{25}\\\\ x^{2}=16\\\\x=\sqrt{16}\\\\x=4\\\\length=4x=4*4=16cm\\\\breadth=3x=3*4=12cm\\\\Perimeter=2*(l+b)\\\\=2*(16+12)=2*28\\\\=56cm

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Allisa [31]

Answer:

<u>-1</u>

2

Step-by-step explanation:

(0,2) and (1,0) are the points on the line

Let (0,2) be (x1,y1) and (1,0) be (x2,y2)

slope(m)= <u>y2-y1</u>

x2-x1

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PLEASE HELP What is the x value??
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Answer:

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Step-by-step explanation:

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2 years ago
Jesse measured a farm and made a scale drawing. The scale of the drawing was 1 centimeter = 4 meters. If the actual width of the
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46 is the answer have a great day
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2 years ago
The American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day. Legacy
inessss [21]

Answer:

We conclude that the null hypothesis is rejected which means residents of Legacy Ranch use less water on average.

Step-by-step explanation:

We are given that the American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day.

Twenty-three owners responded, and the sample mean water use per day was 63 gallons with a standard deviation of 8.1 gallons per day.

<u><em>Let </em></u>\mu<u><em> = average water usage by residents of Legacy Ranch.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 67 gallons     {means that the residents of Legacy Ranch uses more or equal to 67 gallons water on average}

Alternate Hypothesis, H_A : \mu < 67 gallons    {means that the residents of Legacy Ranch use less water on average}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                                 T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean water use per day = 63 gallons

             s = sample standard deviation = 8.1 gallons

             n = sample of responded = 23

So, <u><em>test statistics</em></u>  =  \frac{63-67}{\frac{8.1}{\sqrt{23} } }  ~ t_2_2

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The value of the test statistics is -2.368.

<em>Now at 0.025 significance level, the </em><u><em>t table gives critical value of -2.074 at 22 degree of freedom for left-tailed test</em></u><em>. Since our test statistics is less than the critical values of t as -2.368 < -2.074, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to </em><u><em>which we reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the residents of Legacy Ranch use less water on average.

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Answer:

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