Answer:
could you please explain me the exact question
One number: x
Its consecutive: x + 1
Product:
x(x+1)=121
x² + x - 121 = 0
Δ = 1² - 4.1.(-121)
Δ = 1+484
Δ = 485
As square root of 485 is not integer, do not exist two consecutive numbers with product of 121
There are to be exact only 2 ways to answer this equation because of the way math was made.
