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3 years ago

2. C is at (-5.1) & D is at (7.6). Where is the midpoint on segment CD?

Mathematics

1 answer:

topjm [15]3 years ago

6 0

Answer:

1.25

Step-by-step explanation:

Find the average.

-5.1+7.6=2.5

2.5/2

1.25

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A company produces birthday cards and get well cards at a ratio of 6 to 5 how many birthday cards can ve expected if 60 get well

Alik [6]

The number of birthday cards made is 72.

<h3>Description of ratios</h3>

Ratio expresses the relationship between two numbers. It shows the frequency of the number of times that one value is contained in another number. The sign used to represent ratios is :

<h3>Determining the total cards made. </h3>

Total card = (sum of ratios x number of get well cards) / ratio of get well cards

(11 x 60) / 5 = 132

<h3>Number of birthday cards made </h3>

6/11 x 132 = 72 cards

To learn more about ratios, please check: brainly.com/question/25927869

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2 years ago

Please help, math work

NikAS [45]

Y = 3x + 5 because the slope is 3/1 and 0 = 5

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3 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

(b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

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2 years ago

Identify the ordered pair that represents the vector from a(-9 9) to b(7 3) and the magnitude of AB

Viefleur [7K]

Moving from a to b, the x component of the desired vector is 7-(-9) = 16, and
the y component is 3-9 = -6.

So the vector from a to b is <16,-6>, and the magnitude is

sqrt(16^2 + (-6)^2 ), applying the Pythagorean Theorem.

6 0

2 years ago

Read 2 more answers

Brianne evaluated the expression 42+4(6-2)

Levart [38]

Answer:

Follow the rule of BODMAS (brackets, of, division, multiplication, addition, subtraction)

Ans: 58

Step-by-step explanation:

42 + 4(6 - 2) Process --> 6 - 2 = 4

= 42 + 4 * 4 Process --> 4 * 4 = 16

= 42 + 16 Process --> 42 + 16 = 58

= 58

Hope this helps :)

6 0

2 years ago

2. C is at (-5.1) & D is at (7.6). Where is the midpoint on segment CD?​

2. C is at (-5.1) & D is at (7.6). Where is the midpoint on segment CD?