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3 years ago

Can someone pls help fast

Mathematics

2 answers:

larisa86 [58]3 years ago

8 0

Answer:

i am so sorry but i think the answer is 56

TiliK225 [7]3 years ago

5 0

Answer:

We have the constraint 12x + 8y = 1800 to solve

x and y both have to be positive (she can't work negative hours)

If we choose x = 100 then we have 1200 + 8y = 1800

8y = 1800 - 1200 = 600

y = 75

We know this works because 12 * 100 + 75 * 8 = 1800 which is what she needs.

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Determine the equations of the vertical and horizontal asymptotes if any for h(x)=(x+1)^2/x^2-1

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ANSWER

Vertical asymptote:

x=1

Horizontal asymptote:

y=1

EXPLANATION

The given rational function is

$h(x) = \frac{ {(x + 1)}^{2} }{ {x}^{2} - 1 }$

$h(x) = \frac{ {(x + 1)}^{2} }{ ({x} - 1)(x + 1)}$

$h(x) = \frac{ (x + 1)(x + 1) }{ ({x} - 1)(x + 1)}$

$h(x) = \frac{ x + 1}{ {x} - 1}$

The vertical asymptote occurs at

${x} - 1 = 0$

$x = 1$

The vertical asymptotes is x=1

The degree of the numerator is the same as the degree of the denominator.

The horizontal asymptote of such rational function is found by expressing the coefficient of the leading term in the numerator over that of the denominator.

$y = \frac{1}{1}$

y=1

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