Answer:THANK YOUUUUUUU
Step-by-step explanation:
-x+y=3
y=x+3
2x + x + 3 =6
3x + 3 = 6
3x = 3
x = 1
-1 + y = 3
y = 4
2(1) + y = 6
2 + y = 6
y = 4
Solution: (1, 4)
Answer:
This quadratic equation has 2 solutions.
Step-by-step explanation:
I assume the '?' in your question is meant to be power 2 (²), or else it would not be a quadratic equation. You could write it using the superscript version of 2.
We can solve this equation by expressing it in the form: ax² + bx + c
x² + 9x= -8
x² + 9x + 8 = 0
Now if you know the discriminant, you can simply plug in your values of a, b, and c to see how many solutions there are.
In this case, you would not need the discriminant as there are whole-number factors and hence this can simply be factorised.
x² + 9x + 8 = 0
(x + 8)(x + 1) = 0
For this equation to be true (= 0), x can equal -8 OR -1.
Hence, this quadratic equation has 2 solutions.
Answer:
Read explanation
Step-by-step explanation:
Use elimination
Add them all up
y = 1 ( everything else cancels )
-2x + 2(1) + z = 14
3x - 2(1) + z = -5
-x +(1) - 2z = -8
simplify
-2x + z = 12
3x + z = -3
-x -2z = -9
U can't use elimation because it would turn into 0 = 0
change last equation
x + 2z = 9
x = -2z + 9
plug that in
-2(-2z+9) + z = 12
3(-2z+9) + z = -3
-(-2z+9) - 2z = -9
4z - 18 = 12
-6z + 27 + z =-3
2z - 9 - 2z = -9
simplify
4z = 30
-5z = -30
0 = 0
z = 6
y = 1
x = -3
