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Liula [17]
4 years ago
11

If the mass of a material is 75 grams and the volume of the material is 16 cm3, what would the density of the material be?

Chemistry
2 answers:
DedPeter [7]4 years ago
8 0
Answer:
density = 4.6875 gm / cm³

Explanation:
Density of the material can be calculated using the following rule:
Density = mass / volume

We are given that:
mass = 75 grams
volume = 16 cm³

Substitute with the givens in the above equation to get the density as follows:
density = mass / volume
density = 75 / 16
density = 4.6875 gm / cm³

Hope this helps :)
qwelly [4]4 years ago
7 0
P=75/16=4.6875 g/cm³
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Gaseous compound Q contains only xenon and oxygen. When 0.100 gg of Q is placed in a 50.0 mLmL steel vessel at 0 ∘C∘C, the press
asambeis [7]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.229 atm. What is the likely formula of the compound?

A. XeO

B. XeO_4

C. Xe_2O_2  

D. Xe_2O_3

E. Xe_3O_2

<u>Answer:</u> The chemical formula of the compound is XeO_4

<u>Explanation:</u>

To calculate the molecular mass of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas = 0.229 atm

V = Volume of the gas  = 50.0 mL = 0.050 L     (Conversion factor:  1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas  = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 0^oC=273K

Putting value in above equation, we get:

0.229\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.229\times 0.050}=195.4g/mol\approx 195g/mol

The compound having mass as 195 g/mol is XeO_4

Hence, the chemical formula of the compound is XeO_4

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3 years ago
Predict what would happen if plants disappear?
Yakvenalex [24]

Answer:

All secondary consumers will die because they will lose their food source

7 0
2 years ago
2) What is the concentration of NaCl in a solution prepared by diluting 56.98 ml of 0.5894 M stock
RSB [31]

Answer:

The NaCl concentration will be 0.03 M.

Explanation:

Given data:

Initial volume = V₁ = 56.98 mL (56.98/1000 = 0.05698 L)

Initial concentration = M₁= 0.5894 M

Final volume = V₂= 1.20 L

Final concentration = M₂= ?

Solution:

By diluting the solution volume of solution will increase while number of moles of solute remain the same.

Formula:

Initial concentration × Initial volume  = Final concentration × Final volume

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 0.5894 M × 0.05698 L / 1.20 L

M₂ = 0.0336 M /1.20  

M₂ = 0.03 M

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4 years ago
Where is lipase produced
Ierofanga [76]
It is made by cells in your stomach, but the main source is your pancreas, which is located in your digestive tract.

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A chemistry student needs 30,0 mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the stu
Marta_Voda [28]

Answer:

1.878g

Explanation:

Volume = 30.0ml

Density = 0.626gcm−3

Mass = ?

Be careful in this kind of questions to check for the units. In this case one has to remember 1 mL equal 1 cm³ so density = 0.626g/ml

The relationship between all three parameters is given by the equationn below;

Mass = Density * Volume

Mass = 0.626g/ml * 30 = 1.878g

8 0
3 years ago
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