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3 years ago

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Now suppose, instead, that 5.678 g of a volatile solute is dissolved in 150.0 g of water. This solute also does not react with w

ater nor dissociate in solution. The pure solute displays, at 20°C, a vapour pressure of 1.754 torr. Again, assume an ideal solution. If, at 20°C the vapour pressure of this solution is also 17.344 torr. Calculate the molar mass of this volatile solute.

1 answer:

n200080 [17]3 years ago

4 0

Answer:

59.9 g/mol is the molar mass for the solute

Explanation:

Lowering vapor pressure → ΔP = P° . Xm

P° → Vapor pressure of pure solvent

ΔP = P° - Vapor pressure of solution

Xm = Mole fraction of solute

17.54 Torr - 17.344 Torr = 17.54 Torr . Xm

0.196 Torr / 17.54 Torr = Xm → 0.0112

These are the moles of solute / Total moles

Total moles = Moles of solute + Moles of solvent

We determine the moles of solvent → 150 g . 1mol/ 18 g = 8.33 moles

Now we can make this equation:

0.0112 = Moles of solute / Moles of solute + 8.33 mol

0.0112 Moles of solute + 0.0933 = Moles of solute

0.0933 = Moles of solute - 0.0112 Moles of solute

0.0933 = 0.9888 moles of solute → 0.0933 / 0.9888 = 0.0947 moles

Finally we can determine the molar mass (mol/g)

5.678 g / 0.0947 mol = 59.9 g/mol

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3 years ago

Describe the pattern of the lewis dot structure of the first 18 elements

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Explanation: Lewis dot structures are the structures which represent the valence electrons of an atom. The dots in the structure are considered as the valence electrons.

First 18 elements of the periodic table are Hydrogen(H), Helium (He), Lithium (Li), Beryllium (Be), Boron (B), Carbon (C), Nitrogen (N), Oxygen (O), Fluorine (F), Neon(Ne), Sodium (Na), Magnesium (Mg), Aluminium (Al), Silicon (Si), Phosphorous (P), Sulfur (S), Chlorine (Cl) and Argon(Ar).

The valence electrons are the electrons which are present in the outermost shell of an atom. The electronic configuration of the elements are:

Hydrogen (H) = $1s^1$ ; Valence electrons = 1

Helium (He) = $1s^2$ ; Valence electrons = 2

Lithium (Li) = $1s^22s^1$ ; Valence electrons = 1

Beryllium (Be) = $1s^22s^2$ ; Valence electrons = 2

Boron (B) = $1s^22s^22p^1$ ; Valence electrons = 3

Carbon (C) = $1s^22s^22p^2$ ; Valence electrons = 4

Nitrogen (N) = $1s^22s^22p^3$ ; Valence electrons = 5

Oxygen (O) = $1s^22s^22p^4$ ; Valence electrons = 6

Fluorine (F) = $1s^22s^22p^5$ ; Valence electrons = 7

Neon (Ne) = $1s^22s^22p^6$ ; Valence electrons = 8

Sodium (Na) = $1s^22s^22p^63s^1$ ; Valence electrons = 1

Magnesium (Mg) = $1s^22s^22p^63s^2$ ; Valence electrons = 2

Aluminium (Al) = $1s^22s^22p^63s^23p^1$ ; Valence electrons = 3

Silicon (Si) = $1s^22s^22p^63s^23p^2$ ; Valence electrons = 4

Phosphorous (P) = $1s^22s^22p^63s^23p^3$ ; Valence electrons = 5

Sulfur (S) = $1s^22s^22p^63s^23p^4$ ; Valence electrons = 6

Chlorine(Cl) = $1s^22s^22p^63s^23p^5$ ; Valence electrons = 7

Argon (Ar) = $1s^22s^22p^63s^23p^6$ ; Valence electrons = 8

Elements hydrogen and helium belong to period 1 of the period table, so the lewis dot structures will have maximum of 2 electrons

Elements from lithium to neon belong to period 2 and the lewis dot structures will have maximum of 8 electrons.

Elements from sodium and argon belong to the period 3 of the periodic table, and will have maximum of 8 electrons in their lewis dot structures.

Lewis dot structures are attached below.

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4 years ago

Can someone help me solve this please 2.150 x 10 ^-12 dm / 5.02 x 10 ^-5dm^3

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4.3 x 10⁻⁸dm⁻²

Explanation:

Problem:

$\frac{2.150 x 10^{-12} dm }{5.02 x 10 ^{-5} dm^{3} }$

To solve this problem, we have apply the right rule of indices operation.

If we have an indices in the form;

$\frac{a^{n} }{b^{k} }$ = ( $\frac{a }{b }$ ) $^{n-k}$

Solving this problem:

= $\frac{2.15}{5.02}$ x 10 $^{-12 -(-5}$ )

= 0.43 x 10⁻⁷

= 4.3 x 10⁻¹ x 10⁻⁷

= 4.3 x 10⁻⁸

for the units:

$\frac{dm}{dm^{3} } = \frac{dm}{ dm x dm x dm}$ = $\frac{1}{dm^{2} } = dm^{-2}$

The solution is: 4.3 x 10⁻⁸dm⁻²

learn more:

long division brainly.com/question/1747117

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3 years ago