Seafloor spreading is the answer to your question.
Answer:
T° freezing solution → -11.3°C
T° boiling solution → 103.1 °C
Explanation:
Assuming 100 % dissociation, we must find the i, Van't Hoff factor which means "the ions that are dissolved in solution"
This salt dissociates as this:
SnCl₄ (aq) → 1Sn⁴⁺ (aq) + 4Cl⁻ (aq) (so i =5)
The formula for the colligative property of freezing point depression and boiling point elevation are:
ΔT = Kf . m . i
where ΔT = T° freezing pure solvent - T° freezing solution
ΔT = Kb . m . i
where ΔT = T° boiling solution - T° boiling pure solvent
Freezing point depression:
0° - T° freezing solution = 1.86°C/m . 1.22 m . 5
T° freezing solution = - (1.86°C/m . 1.22 m . 5) → -11.3°C
Boiling point elevation:
T° boiling solution - 100°C = 0.512 °C/m . 1.22 m . 5
T° boiling solution = (0.512 °C/m . 1.22 m . 5) + 100°C → 103.1 °C
The carbon atoms that will be
in the longest chain of 2, 2, 4 – trimethyl pentane is 5. There are 5 carbons
in the longest chain that forms a cross.
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Limestone is calcium carbonate Ca(Co3) it's dissociation equation is as follows:
Ca(CO3) <----> Ca+2 + CO3-2
but the solubility is very small
in the presence of acid by LeChatlier's Principle you can shift to the right by adding acid
H+ + CO3-2 <-----> H+CO3- (the bicarbonate ion which is really soluble)
The system will pull more and more limestone out into solution as acid is added and neutralize the acid coming from the rain.
