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babymother [125]
3 years ago
12

Quickly, please, this is timed.

Mathematics
1 answer:
o-na [289]3 years ago
8 0

Answer:

it is the bottom one

Step-by-step explanation:

i think i could be wrong

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HELP ASAP, PLEASE!!!!​
padilas [110]

Answer:

Fraction = 5/10 = 1/2

Decimal = 0.5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The equation of a circle is x2 + y2 + 6x + 4y + 10 = 1. What is this equation written in its standard form?
Over [174]
You need to complete the square in x and in y,

x^{2}  + y^{2} + 6x + 4y + 10 = 1

First, group the x-terms and the y-terms separately.

x^{2} + 6x  + y^{2} + 4y + 10 = 1

Move the 10 to the right side by subtracting 10 from both sides.

x^{2} + 6x  + y^{2} + 4y = -9

Now complete the square in x and in y.
The constant you need to add to complete each square is the square of half of the coefficient of the x or y term. Make sure to add the constants to both sides of the equation.

x^{2} + 6x  + 9 + y^{2} + 4y + 4= -9 + 9 + 4

(x + 3)^{2} + (y + 2)^{2} = 4
8 0
3 years ago
Which angle is complementary to
erastovalidia [21]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you need to write complete questions in order to find good and exact answers. Here your question is incomplete so I could help you in a general way. Recall that two angles are complementary if and only if they add up to 90°. So, if we have to angles, namely:

∠A and ∠B

And angle ∠A = 35°, then this is complementary to ∠B as the following form:

∠A + ∠B = 90°

∴ 35° + ∠B = 90°

∴ ∠B = 90° - 35°

∴ ∠B = 55°

Finally, ∠A and ∠B are complementary because they add up to 90°

4 0
3 years ago
Solve for x: -5x + 8(2x -3) = x - 4(x + 1)
White raven [17]
Exact Form:
X=10/7

Decimal Form:
X=1.428571

Mixed Number Form:
X= 1 3/7
6 0
3 years ago
How do you find a vector of length 10 in the direction of v equals=left angle 3 comma negative 2 right angle 3,−2?
olya-2409 [2.1K]

Your vector will be 10 times the unit vector in that direction. The unit vector is found by dividing the given vector by its length.

|| <3, -2> || = √(3² +(-2)²) = √13

Your vector of length 10 is then

... V = (10/√13)<3, -2> = <(30/13)√13, (-20/13)√13> ≈ <8.32, -5.55>

4 0
3 years ago
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