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MrMuchimi
3 years ago
9

What is the solution to the following inequality? 14 <-7x

Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

Therefore x >-2

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50 POINTS IF YOU HELP!!!!!
DaniilM [7]
We know that

[the area of a circle]=pi*r²
for r=4 ft
[the area of a circle]=pi*4²------> 50.24 ft²

if 2π radians ( full circle) has an area of-----------------> 50.24 ft²
5π/2 radians--------------------------------------> X ft ²
X=(5π/2)*50.24/2π-------> 62.8 ft²

the answer is
62.8 ft²
8 0
3 years ago
Read 2 more answers
My sis needs help asap
Alika [10]

Answer:

3/4 - 5/12

Step-by-step explanation:

first you make the demoninators the same so 3*4=12

and if you *3 you do it to the numerator

so its 9/12-5/12

the unsimplified fraction is 4/12

if wanted simplified version its 1/3

3 0
1 year ago
Read 2 more answers
Can someone help with this questions please
MrRissso [65]
Q9. 

This question can't be answered. It is necessary to get the dimensions of the figure.

Q10. 

Let's find a conclusion having statements step by step.

a) If 3 cans of soup cost a total of $0.85, then 1 can of soup costs:

\frac{\$0.85}{3}

b) If I get n cans of soup the equation I need to use is multiply the previous equation by n:

(\frac{\$0.85}{3})n

The conclusion is: G. Multiplying n by the cost of 1 can.

Q11. 

Let's find a conclusion having statements step by step.

a) The company charges $40 to hook a vehicle, so this is a constant variable. Then:

c = 40$

b) There is a second statement that states that for each mile the vehicle is towed the cost increases $1.70, so:

c = $40 + 1.70m

So, the answer is B.



7 0
2 years ago
What Is the answer? <br><img src="https://tex.z-dn.net/?f=6x%20%2B%202%20%2B%206x%20%3C%2014" id="TexFormula1" title="6x + 2 + 6
timofeeve [1]

6x+2+6x<14

add 6x+6x

12x+2<14

subtract 2 from both sides

12x<12

divide by 12

x<1

5 0
3 years ago
Can help with this please​
madam [21]

Answer:

m∠8 = 4x

Step-by-step explanation:

Angle 8 is the same angle measure of angle 1, which is m∠1 = 4x

7 0
3 years ago
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