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3 years ago

Need help asapdue today at 11 am

Mathematics

1 answer:

goblinko [34]3 years ago

8 0

12 × 8 = 96 3 × 3 = 9 96 - 9 = 87

(unlucky jasmine she does not have enough paint )

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Which inequality's solution is graphed here?

blagie [28]

The answer to this inequality solution is 6x+42<0

7 0

3 years ago

...... trying to find domain, range rel max rel min end behavior inc intervals dec intervals. zeros..... I'm a mom trying to hel

Fiesta28 [93]

Answer:

The values are evaluated below.

Step-by-step explanation:

Given function is

$-x^4-7x^3-12x^2$

We have to find the domain, range, rel max, rel min, end behaviour, increasing or decreasing intervals and zeros of polynomial.

Domain:

The domain of a function is the set of all possible values of x for the given function.

Here domain is set of all real numbers R.

Range:

The range is the resulting y-values we get after substituting all the possible x-values.From the graph we see that

The range is $-\infty$

Relative maxima and minima of a function, are the largest and smallest value of the function on an entire domain of function.

Relative max of $-x^4-7x^3-12x^2$ is 0 at x=0

and $\frac{3}{512}(133\sqrt57-471)$ at $x=\frac{-21}{8}-\frac{\sqrt57}{8}$

Relative min is

$\frac{-3}{512}(471+133\sqrt57)$ at $x=\frac{-21}{8}+\frac{\sqrt57}{8}$

From the graph we see that

End behaviour is As $\\x->\infty, f(x)->-\infty\\x->-\infty, f(x)->-\infty\\$

Increasing intervals and decreasing intervals are

Increasing: $\frac{1}{8}(\sqrt57-21)$

Decreasing: $\frac{1}{8}(-21-\sqrt57)$

Zeroes are :

$-x^4-7x^3-12x^2=0$

⇒ $(-x^2)(x^2+7x+12)=0$

⇒ $(-x^2)(x+3)(x+4)=0$

Hence, zeroes are 0, 0, -3, -4

3 0

3 years ago

Read 2 more answers

If the length of an arc is 12 inches and the radius of the circle is 10 inches, what is the measure of the arc?

a_sh-v [17]

I guess what you are asking is what is the measure of the central angle?

arc length = radius * central angle (in radians)

central angle (in radians) = arc length / radius

central angle (in radians) = 12 / 10

central angle (in radians) = 1.2 radians = 68.7549 degrees

3 0

3 years ago

If the basalt at the top of the ancient valley below Vulcan's Throne yields a radiometric date (K-Ar) of 15,000 years, and the l

zepelin [54]

Answer:

$1.69\times 10^3$ feet/million year

Step-by-step explanation:

We are given that

Elevation of top of basalt in valley =4100 feet

Elevation of bottom of basalt in valley =2100 feet

Age of top of basalt in valley=15000 years

Age of bottom of basalt in valley=1.2 million years= $1.2\times 10^6 years=1200000 years$

We have to find the rate of basalt filling in the valley in feet per million yeas

Rate of basalt filling in the valley= $\frac{Elevation\;of\;top\;of\;basalt\;in\;valley-elevation\;of\;bottom\;of\;basalt\;in\;valley}{age\;of\;bottom\;of\;basalt\;in\;valley-age\;of\;top\;of\;basalt\;in\;valley}$