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garri49 [273]
3 years ago
7

A magician showed a magic trick where he picked one card from a standard deck. Determined what the probability is that the card

will be a red color or a queen card?
Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0

Answer:

7 / 13

Step-by-step explanation:

The number of cards in a standard deck = 52

Number of red cards in a deck = 26

Number of queens in a deck = 4

Selecting a card at random ;

Probability of picking a red card ;

P(red card) = number of red cards / number of cards in deck

P(red card) = 26 / 52

P(queens card) = number of queens / number of cards in deck

P(queens card) = 4 / 52

Number of red queen cards = (red n queen) = 2

P(red or queens card) = P(red) + P(queens) - P(red n queen)

P(red or queens card) = 26/52 + 4/52 - 2/52

= (26 + 4 - 2) / 52

= 28 /52

= 7 / 13

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Ierofanga [76]

It's given in the question,

P, Q, V and K are collinear.

VP = 14x + 4

PK = x + 630

VQ = 17x + 6

KQ = 11x + 5

By segment addition postulate,

KQ + VQ + VP = KP

Substitute the values in the expression,

(11x + 5) + (17x + 6) + (14x + 4) = x + 630

(11x + 17x + 14x) + (5 + 6 + 4) = x + 630

42x + 15 = x + 630

42x - x = 630 - 15

41x = 615

x = \frac{615}{41}

x = 15

Therefore, value of VP = (14x + 4)

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                                      = 214 units

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