Answer:
x = ±i(√6 / 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
<u>Algebra II</u>
Imaginary root i
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2x² + 3 = 0
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 3 on both sides: 2x² = -3
- [Division Property of Equality] Divide 2 on both sides: x² = -3/2
- [Equality Property] Square root both sides: x = ±√(-3/2)
- Simplify: x = ±i(√6 / 2)
Answer:
5 and -5 (±5)
Step-by-step explanation:
x²-8=17
x²=25
√x²=√25
x=±5
Answer:
i think the answer is C
sorry if i am wrong
Step-by-step explanation:
Answer:
J(2, 5 )
Step-by-step explanation:
Using the section formula
= 
= 
= 
= 2
= 
= 
= 
= 5
Thus J = (2, 5 )
That would be the same as : 10 × (x + 8)
Okay, so it's asking for the product of 10, and the sum of 8 and k. Sum is the answer to an addition problem, so that would make the last of it 8 + k. And we'd be multiplying this with 10, so that would make it : 10 × (x + 8)
