Inverse variation:
![y=\frac{k}{x}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bk%7D%7Bx%7D)
k is a constant
Use the given information (when x=4 y=4) to find the value of the constant:
![\begin{gathered} 4=\frac{k}{4} \\ \\ \text{Multiply both sides of the equation by 4:} \\ 4\times4=4\times\frac{k}{4} \\ \\ 16=k \\ \\ \\ k=16 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%204%3D%5Cfrac%7Bk%7D%7B4%7D%20%5C%5C%20%20%5C%5C%20%5Ctext%7BMultiply%20both%20sides%20of%20the%20equation%20by%204%3A%7D%20%5C%5C%204%5Ctimes4%3D4%5Ctimes%5Cfrac%7Bk%7D%7B4%7D%20%5C%5C%20%20%5C%5C%2016%3Dk%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20k%3D16%20%5Cend%7Bgathered%7D)
Then, the given relationship has the next equation:
![y=\frac{16}{x}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B16%7D%7Bx%7D)
Use the equation above to find y when x=2:
![\begin{gathered} y=\frac{16}{2} \\ \\ y=8 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%3D%5Cfrac%7B16%7D%7B2%7D%20%5C%5C%20%20%5C%5C%20y%3D8%20%5Cend%7Bgathered%7D)
Then, when x=2, y=8
Answer:
3(2x+11)= 6x+33 and (3x+15)(2) = 6x+30
Step-by-step explanation:
Use distributive property to multiply the outside factor to each factor inside the parenthesis.
3(2x+11)
(3*2x)+(3*11)
6x+33
All of those numbers are rational, except the square root of 12.