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Virty [35]
2 years ago
15

Given the balanced equation: Pb(NO₃)₂(aq) + 2NaCl(aq) ➔ PbCl₂(s) + 2NaNO₃(aq). What type of reaction is represented by this equa

tion
Chemistry
1 answer:
Lilit [14]2 years ago
5 0

Answer: The given reaction is a double displacement reaction.

Explanation:

A chemical reaction in which two different compounds chemically react with each other by switching places of both positive and negative ions is known as a double displacement reaction.

For example, Pb(NO_3)_2(aq) + 2NaCl(aq) \rightarrow PbCl_2(s) + 2NaNO_3(aq)

Here, both Pb^{2+} and Na^{+} ions switched places. Also, both (NO_3)^{-}_{2} and Cl^{-} ions switched places.

Therefore, we can conclude that the given reaction is a double displacement reaction.

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jeyben [28]

Answer: The correct answer is in chemical bonds

Explanation:

When coal is burnt, these components burn and release energy. The energy released is by the chemical reaction between the constituents and oxygen

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2 years ago
What is the name of Pb(NO3)2? Explain how you determined the bond type and the steps you used to determine the naming convention
Elena L [17]

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Explanation:

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2 years ago
7 f Find the volume in dm3 and in mole of 0.505m of NaoH required to react with 40ml of 0.505m
Anna [14]

The volume of NaOH required is 0.08 dm³

To solve this question, we'll begin by writing the balanced equation for the reaction between H₂SO₄ and NaOH. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

Mole ratio of the acid, H₂SO₄ (n_{A}) = 1

Mole ratio of the base, NaOH (n_{B}) = 2

Next, we shall determine the volume of NaOH required to react with H₂SO₄. This can be obtained as follow:

Molarity of the base, NaOH (M_{B}) = 0.505 M

Volume of the acid, H₂SO₄ (V_{A}) = 40 mL

Molarity of the acid, H₂SO₄ (M_{A}) = 0.505 M

<h3>Volume of the base, NaOH (V_{B}) =? </h3>

\frac{M_{A} * V_{A}}{M_{B} * V_{B}} = \frac{n_{A}}{n_{B}}\\\\\frac{0.505 * 40}{0.505 *V_{B}} = \frac{1}{2}\\\\\frac{20.2}{0.505 *V_{B}} = \frac{1}{2}

Cross multiply

0.505 * V_{B} = 20.2 * 2\\0.505 * V_{B} = 40.4

Divide both side by 0.505

V_{B} = \frac{40.4}{0.505}\\\\V_{B} = 80 mL

Finally, we shall convert 80 mL to dm³. This can be obtained as follow:

1000 mL = 1 dm^{3}\\\\Therefore,\\\\80 mL = \frac{80 mL * 1dm^{3}}{1000 mL}\\\\80 mL = 0.08dm^{3}

Therefore, the volume of NaOH required is 0.08 dm³

Learn more: brainly.com/question/19053582

3 0
2 years ago
Potassium permanganate as a symbol
Alexxx [7]

Answer: KMnO4-

Explanation:

You're looking at one potassium plus a polyatomic ion.

So K plus MnO4, equals:

KMnO4-

It also has a molar mass of 158.04 g/mol, I don't know if you need that, but I thought it would be nice to include it.

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Answer:

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