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3 years ago

A thermodynamic cycle which works to cause heat to flow from a cold resorption to a hotter reservoir is called?

Chemistry

2 answers:

Anni [7]3 years ago

5 0

Answer:

a. a heat reservoir

Explanation:

Flauer [41]3 years ago

4 0

Answer:

a and c

Explanation:

I ain't sure I legit found ur quiz do u want me to do it and send the anwsers?

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true or false electrical energy is the amount of energy that contains an object due to the kinetic energy?

yuradex [85]

The answer to this question would be true.

4 0

3 years ago

Calculate ΔHo for the following reaction ussing the given bond dissociation energiesCH4(g) + 2O2(g) --> CO2(g) + 2H2O(g)BOND

Mazyrski [523]

Answer:

The ΔH° for the following reaction is -794 kJ, hence exothermic reaction,

Explanation:

$CH_4(g) + 2O_2(g)\rightarrow CO_2(g) + 2H_2O(g) ,$ ΔH° = ?

We are given with:

$\Delta H_{O-O}=142 kJ/mol$

$\Delta H_{O=O}=498 kJ/mol$

$\Delta H_{H-O}=459 kJ/mol$

$\Delta H_{C-H}=411 kJ/mol$

$\Delta H_{C-O}=358 kJ/mol$

$\Delta H_{C=O}=799 kJ/mol$

ΔH° =

(Energies required to break bonds on reactant side) - (Energies released on formation of bonds on product side)

$\Delta H^o=(1 mol\times 4\times \Delta H_{C-H}+2 mol\times 1\times \Delta H_{O=O})-(1 mol\times 2\times \Delta H_{C=O}+2 mol\times 2\times\Delta H_{H-O})$

$\Delta H^o=(1 mol\times 4\times 411 kJ/mol+2 mol\times 1\times 498 kJ/mol)-(1 mol\times 2\times 799 kJ/mol+2 mol\times 2\times 459 kJ/mol)$

$\Delta H^o=-794kJ$

$\Delta H^o>0$ endothermic reaction

$\Delta H^o$ exothermic reaction

The ΔH° for the following reaction is -794 kJ, hence exothermic reaction,

4 0

4 years ago

Identify the compound that has polar bonds, but a dipole moment of 0. identify the compound that has polar bonds, but a dipole m

matrenka [14]

CF4 is the compound that has polar bonds, but dipole moment of O. C-f bond is a polar bond which is covalent. It has dipole of 4 polar C.F bonds and results in the overall monopolar molecule.
CF4 it has no net dipole moment.

4 0

3 years ago

Read 2 more answers

The pH of a 0.25 M (aq) solution of hydrofluoric acid, HF, at 25C is 2.03. What is the value of Ka for HF? Pls show all mathemat

Snezhnost [94]

Answer:

Explanation:

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4 0

3 years ago

2Pb(s) + O2(aq) + 4H+(aq) → 2H2O(l) + 2Pb2+(aq)

defon

Answer:

The answer to your question is 0.269 g of Pb

Explanation:

Data

Lead solution = 0.000013 M

Volume = 100 L

mass = 0.269 g

atomic mass Pb = 207.2 g

Chemical reaction

2Pb(s) + O₂(aq) + 4H⁺(aq) → 2H₂O(l) + 2Pb₂⁺(aq)

Process

1.- Calculate the mass of Pb in solution

Formula

Molarity = $\frac{number of moles}{volume}$

Solve for number of moles

Number of moles = Volume x Molarity

Substitution

Number of moles = 100 x 0.000013

Number of moles = 0.0013

2.- Calculate the mass of Pb formed.

207.2 g of Pb ----------------- 1 mol

x g ----------------- 0.0013 moles

x = (0.0013 x 207.2) / 1

x = 0.269 g of Pb

8 0

4 years ago

Read 2 more answers