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butalik [34]
3 years ago
13

2Pb(s) + O2(aq) + 4H+(aq) → 2H2O(l) + 2Pb2+(aq)

Chemistry
2 answers:
defon3 years ago
8 0

Answer:

The answer to your question is 0.269 g of Pb

Explanation:

Data

Lead solution = 0.000013 M

Volume = 100 L

mass = 0.269 g

atomic mass Pb = 207.2 g

Chemical reaction

                        2Pb(s) + O₂(aq) + 4H⁺(aq) → 2H₂O(l) + 2Pb₂⁺(aq)

Process

1.- Calculate the mass of Pb in solution

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

Number of moles = Volume x Molarity

Substitution

Number of moles = 100 x 0.000013

Number of moles = 0.0013

2.- Calculate the mass of Pb formed.

                       207.2 g of Pb ----------------- 1 mol

                             x g             ----------------- 0.0013 moles

                        x = (0.0013 x 207.2) / 1

                        x = 0.269 g of Pb                                                                

Step2247 [10]3 years ago
4 0

Answer:

0.269 grams of lead metal reacted

Explanation:

Step 1: Data given

Volume of a 0.000013M lead solution = 100 L

Molar mass of Pb = 207.2 g/mol

Step 2: The balanced equation

2Pb(s) + O2(aq) + 4H+(aq) → 2H2O(l) + 2Pb^2+(aq)

Step 3: Calculate moles of lead

Moles Pb^2+ = molarity * volume

Moles Pb^2+ = 0.000013M * 100L

Moles Pb^2+ = 0.00130 moles

Step 4: Calculate moles Pb metal

For 2 moles Pb we need 1 mol O2 and 4 moles H+ to produce 2 moles H2O and 2 moles Pb^2+

For 0.00130 moles Pb^2+ produced we need 0.00130 moles Pb

Step 5: Calculate mass of Pb

Mass Pb = moles Pb * molar mass Pb

Mass Pb = 0.00130 moles * 207.2 g/mol

Mass Pb =  0.269 grams

0.269 grams of lead metal reacted

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Answer:

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6 0
2 years ago
What is the density of an object that has a mass of 6.5 g and when placed in water displaces the volume from 4.5mL to 11.8mL? ro
KengaRu [80]

Answer:

\rho =0.9g/mL

Explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

V=11.8mL-4.5mL=7.3 mL

In such a way, considering the mathematical definition of density, it turns out:

\rho =\frac{m}{V}=\frac{6.5g}{7.3mL}\\  \\\rho =0.89g/mL

Rounding to the nearest tenth we finally obtain:

\rho =0.9g/mL

Regards.

3 0
3 years ago
2 HCl + Na2SO4 > 2 NaCl + H2SO4
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Answer:

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Explanation:

8 0
2 years ago
Consider the titration of 10.00 mL of a monoprotic weak acid with 0.1234 M NaOH. If the equivalence point volume of NaOH was det
gogolik [260]

The initial concentration of the unknown acid is 0.1900 M.

Explanation:

Titration is a chemical method of analysis to know the concentration and volume of the unknown chemical or analyte.

The formula for the titration is:

Macid x Vacid = Mbase x V base

The volume must be in litres. The volume is given in ml it should be divided with 1000 to obtain values in litre.

Data given are:

volume of acid= 10 ml 0.01 L

Molarity of the acid = ?

volume of the NaOH or base = 15.4 ml or 0.0154 L (equivalence point of the base)

molarity of the base = 0.1234 M

Applying the formula and putting the values, we get

Macid x 0.01 = 0.1234 x 0.0154

Macid =  0.1900 M

The weak acid is having molarity of 0.1900 M against the strong base with molarity of 0.1234M.

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