The molarity of the diluted solution is 0.32 M
Considering the question given above, the following data were obtained:
Volume of stock solution (V₁) = 500 mL
Molarity of stock solution (M₁) = 2.1 M
Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL
<h3>Molarity of diluted solution (M₂) =....? </h3>
The molarity of the diluted solution can be obtained as follow:
<h3>M₁V₁ = M₂V₂</h3>
2.1 × 500 = M₂ × 3250
1050 = M₂ × 3250
<h3>Divide both side by 3250</h3><h3 />
M₂ = 1050 / 3250
<h3>M₂ = 0.32 M</h3>
Therefore, the molarity of the diluted solution is 0.32 M
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Using stoichiometry:
5.5 L of blood x (1000 mL/1L) x (15 g/100 mL) x (1 kg/1000 g) = 0.825 kg
Answer:
1520mmHg
Explanation:
Data obtained from the question include:
V1 (initial volume) = 600 mL
P1 (initial pressure) = 760 mmHg
V2 (final volume) = 300 mL
P2 (final pressure) =.?
Using the Boyle's law equation P1V1 = P2V2, the final pressure of the gas can easily be obtained as shown below:
P1V1 = P2V2
760 x 600 = P2 x 300
Divide both side by 300
P2 = (760 x 600) /300
P2 = 1520mmHg
The final pressure of the gas is 1520mmHg
Three peaks corresponding to Cl+2 will be recorded. The peaks are for isotope 35, both 35 and 37 and for isotope 37. Mass spectrometer has the ability to detect and separate isotopes, even those differing by a single atomic mass unit. When chlorine isotopes are analysed by mass spectrometer, either peak M or M+2 can be obtained. The intensity ratio in the isotope pattern depends on the natural abundance of the isotopes.
A carbonate because the oxygen neutralizes the reactive coding of the calcium in its original form.
