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yan [13]
3 years ago
5

How many atoms are in 65.05g of Na?​

Chemistry
1 answer:
Artemon [7]3 years ago
7 0

Answer:

grsdg

Explanation:

sadga

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How much energy would be released as an electron moved from the n=4 to the n=3 energy level?
Thepotemich [5.8K]

The energy released when electron move from n=4 to n=3 is 0.66 eV

We know that in an atom energy of nth state is

                                     E_n =  -13.6/n^{2}  eV

where n is the energy level

Therefore,

                   E_4 = -13.6/4^{2} \\E_3  = -13.6/3^{2}

Thus, E_4  =   -0.85eV

         E_3  =  -1.51eV

Therefore, total mount of energy released in moving electron from n=4 to n=3 is given by -

                                       E_4 -E_3

                                   =  -0.85 - ( -1.51)

                                   = 0.66eV

To know more about energy released in electron transition

brainly.com/question/8384785

#SPJ4

8 0
2 years ago
using the symbol M for the element, write the chemical formula for the compound that forms when element M reacts with iodine.
Anon25 [30]

Answer : The chemical formula for the compound is, MI

Explanation :

When the element 'M' react with the I_2 to give MI.

The balanced chemical reaction is,

2M+I_2\rightarrow 2MI

In this reaction, 'M' is in mono-atomic form and I_2 is in diatomic form.

By the stoichiometry,

2 moles 'M' react with the 1 mole of I_2 to give 2 moles of MI.

Therefore, the chemical formula of the compound is, MI


6 0
3 years ago
Read 2 more answers
Which type of radioactive decay can pass through the body?
Mkey [24]
Q. Which type of radioactive decay can pass through the body?

A. Gamma Rays
3 0
3 years ago
Calculate the rate of dissolution (dM/dt) of relatively hydrophobic drug particles with a surface area of 2.5×103 cm2 and satura
Crank

Answer:

\large \boxed{\text{1.22 mg/s}}

Explanation:

We can use the Noyes-Whitney equation to calculate the rate of dissolution.

\dfrac{\text{d}M}{\text{d}t} = \dfrac{DA(C_{s} - C)}{d}

Data:

D = 1.75 × 10⁻⁷ cm²s⁻¹

A = 2.5 × 10³ cm²

Cₛ = 0.35 mg/mL

C = 2.1 × 10⁻⁴ mg/mL

d = 1.25 µm

Calculations:

Cₛ - C = (0.35 - 2.1 × 10⁻⁴) mg·cm⁻³ = 0.350 mg·cm⁻³

d = 1.25 µm = 1.25 × 10⁻⁶ m = 1.25 × 10⁻⁴ cm

\dfrac{\text{d}M}{\text{d}t} = \dfrac{(1.75 \times 10^{-7} \text{cm}^{2}\text{s}^{-1})(2.5 \times 10^{3} \text{ cm}^{2})(0.350\text{ mg$\cdot$cm$^{-3}$})}{1.25 \times 10^{-4} \text{ cm}} = \textbf{1.22 mg/s}\\\\\text{The rate of dissolution is $\large \boxed{\textbf{1.22 mg/s}}$}

8 0
3 years ago
Helppp meee outtttt
MArishka [77]
The answer is B 80 grams
3 0
3 years ago
Read 2 more answers
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