Answer:
Brown color of the solution decreases
Explanation:
is brown in color whereas
is colorless.
Equilibrium reaction between
and
is as follows:

As per the Le Chatelier's principle, if pressure of a equilibrium is increased, the equilibrium will shift in the direction having fewer no. of moles of gases.
In the given equilibrium,
side has more no. of moles. So on increasing pressure, equilibrium will shift towards the side of
or more formation of
will take place.
Therefore, more
will decompose that will decrease the brown color of the solution as
is colorless.
Answer:
Explanation:
Polar molecules interact with other molecules of similar polarity to form solutions. Non-polar molecules do not interact the same way.
For the reactants,
- The oxidation number of hydrogen = +1
- The oxidation number of oxygen = -2
- The oxidation number of arsenic = +5
- The oxidation number of carbon = +3
For the products,
- The oxidation number of hydrogen = +1
- The oxidation number of oxygen = -2
- The oxidation number of arsenic = +3
- The oxidation number of carbon = +4
Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.
Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.
Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.
So, the answers are:
name of the element oxidized: Carbon
name of the element reduced: Arsenic
formula of the oxidizing agent: 
formula of the reducing agent: 
The senate only allows two senates from each state.