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Montano1993 [528]
3 years ago
11

A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. What is the final volume, in liters, when each of the foll

owing changes occurs in the quantity of the gas at a constant pressure and temperature?
A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.
B. A sample of 2.00 g of O2 is removed.
C. A sample of 4.00 g of O2 is added to the 4.80 g of O2 gas in the container.
Chemistry
1 answer:
neonofarm [45]3 years ago
4 0
The correct answer for the question that is being presented above is this one: "A. A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container." A sample containing 4.80 g of O2 gas has an initial volume of 15.0 L. The final volume, in liters, when each of the following changes occurs in the quantity of the gas at a constant pressure and temperature is that <span>A sample of 0.500 mole of O2 is added to the 4.80 g of O2 in the container.</span>
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Compared to rodents, rabbits have an extra pair of incisors and other skeletal structures that are different. They also have som
Alexxandr [17]

Compared to rodents, rabbits have an extra pair of incisors and other skeletal structures that are different, scientist can conclude from this observation that they are serially homologous.

<h3>What are serially homologous?</h3>

Serial homologous organs or structures are those that are structurally similar but have been modified to perform distinct functions.

As rodents and rabbits both have some similar functions and some changes in the skeletal structure, so that they both are serially homologous.

Hence scientist conclude that rodents and rabbits are serially homologous animals.

To know more about serially homologous, visit the below link:
brainly.com/question/20577219

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6 0
1 year ago
The length of a sheet of U.S standard (letter size) paper is closest to: 8 centimeters 11 centimeters 29 centimeter 300 centimet
s2008m [1.1K]
US Letter is a paper size, which measures:
8.5 inches ( width ) by 11.0 inches ( length ).
8.5 inches = 21.59 cm
11.0 inches = 27.94 cm
The length ( 27.94 cm ) is closest to 29 cm.
Answer:
C ) 29 cm
6 0
2 years ago
In order to participate in a hydrogen bond, a hydrogen atom must be covalently bonded to one of three elements. What are they?
Lyrx [107]

Oxygen, Nitrogen and Fluorine

Explanation:

In order to participate in a hydrogen bond, a hydrogen atom must be covalently bonded to one of the oxygen, nitrogen and fluorine.

  • Hydrogen bonding is a type of dipole - dipole attraction between two specie.
  • It is an intermolecular force of attraction.
  • This bond type forms when hydrogen is bonded to a more electronegative atom.
  • These atoms are oxygen, nitrogen and fluorine
  • These species draws the electron shared more to themselves and leaves a partial positive charge on the hydrogen and a negative charge on them.
  • The electrostatic force of attraction between the hydrogen of one molecule and the O/N/F of another molecule cause the formation of hydrogen bonds.

learn more:

Hydrogen bonding brainly.com/question/10602513

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5 0
2 years ago
The titration of 25.0 mL of an iron(II) solution required 18.0 mL of a 0.145 M solution of dichromate to reach the equivalence p
Svetlanka [38]

Answer:

0.64 M

Explanation:

Given:

Volume of iron(II) solution (V₁) = 25.0 mL = 0.025 L

Molarity of iron(II) solution (M₁) = ?

Number of moles of iron(II) solution (n₁) = ?

Volume of dichromate solution (V₂) = 18.0 mL = 0.018 L

Molarity of dichromate solution (M₂) = 0.145 M

Number of moles of dichromate solution (n₂) = ?

Molarity is equal to the ratio of moles and volume.

So, molarity of dichromate solution is given as:

M_2=\frac{n_2}{V_2}\\\\n_2=M_2\times V_2=0.145\times 0.018 = 2.61\times 10^{-3}\ mol

Now, let us write the complete balanced reaction for the given situation.

So, the complete balanced equation is given below.

6Fe^{2+}(aq)+Cr_2O_7^{2-}(aq)+14H^+(aq)\to 6Fe^{3+}(aq)+2Cr^{3+}(aq)+7H_2O

From the equation, it is clear that, 1 mole of dichromate is required for 6 moles of iron(II) solution.

So, using unitary method, we find the number of moles of iron(II) solution.

1 mole of dichromate = 6 moles of iron(II)

∴ n₂ moles of dichromate = 6n₂ moles of iron(II)

                                          = 6\times 2.61\times 10^{-3}=0.016\ mol\ Fe^{2+}

So, 0.016 moles of iron(II) is needed. Therefore, n_1=0.016\ mol

Now, molarity of iron(II) solution is given as:

Molarity = Moles ÷ Volume

M_1=\frac{n_1}{V_1}\\\\M_1=\frac{0.016\ mol}{0.025\ L}=0.64\ M

Therefore, the molarity of the iron(II) solution is 0.64 M.

4 0
3 years ago
10 elements and what you know about their properties and reactions.
marta [7]

Answer:

Hydrogen. H.

Helium. He.

Lithium. Li.

Beryllium. Be.

Boron. B.

Carbon. C.

Nitrogen. N.

Oxygen. O.

Fluorine

Neon

Explanation:

6 0
3 years ago
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