Some G protein‑coupled receptors are sensitive to hormones such as angiotensin II and oxytocin and act through compounds such as
phospholipase C and IP3 . Complete the flowchart showing the cleavage of a membrane lipid to form compounds that ultimately cause the phosphorylation of specific proteins. The abbreviations used are phosphatidylinositol 4,5‑bisphosphate, PIP2 ; protein kinase C, PKC ; diacylglycerol, DAG ; inositol 1,4,5‑triphosphate, IP3 ; and phospholipase C, PLC . Which of the compounds can be considered second messengers? DAG Ser PLC Ca2+ IP3 PKC PIP2
1 answer:
Answer:
see explaination
Explanation:
a. Please kindly check attachment for the detailed solution.
b.
The molecules that relay signals, which are received at receptors to the target sites is called second messengers. The three major classes of second messengers are cyclic nucleotides, IP3 & DAG, and calcium ions. Thus, the different second messengers in the body are cAMP, cGMP, IP3, DAG, and Ca2+.
Thus, in the given case the correct options among the following are 1, 4, and 7.
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0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.
Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions.
The balanced neutralization equation is:
NaOH(aq) + KHC₈H₄O₄(aq) ⇒ KNaC₈H₄O₄(aq) + H₂O(l)
- Step 1: Calculate the reacting moles of KHP.
0.212 g of KHP react. The molar mass of KHP is 204.22 g/mol.
0.212 g × 1 mol/204.22 g = 1.04 × 10⁻³ mol
- Step 2: Determine the reacting moles of NaOH.
The molar ratio of NaOH to KHP is 1:1.
1.04 × 10⁻³ mol KHP × 1 mol NaOH/1 mol KHP = 1.04 × 10⁻³ mol NaOH
- Step 3: Calculate the molarity of NaOH.
1.04 × 10⁻³ moles of NaOH are in 35.00 mL of solution.
[NaOH] = 1.04 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.0297 M
0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.
Learn more about titration here: brainly.com/question/4225093
