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Grace [21]
3 years ago
14

Some G protein‑coupled receptors are sensitive to hormones such as angiotensin II and oxytocin and act through compounds such as

phospholipase C and IP3 . Complete the flowchart showing the cleavage of a membrane lipid to form compounds that ultimately cause the phosphorylation of specific proteins. The abbreviations used are phosphatidylinositol 4,5‑bisphosphate, PIP2 ; protein kinase C, PKC ; diacylglycerol, DAG ; inositol 1,4,5‑triphosphate, IP3 ; and phospholipase C, PLC . Which of the compounds can be considered second messengers? DAG Ser PLC Ca2+ IP3 PKC PIP2

Chemistry
1 answer:
labwork [276]3 years ago
4 0

Answer:

see explaination

Explanation:

a. Please kindly check attachment for the detailed solution.

b.

The molecules that relay signals, which are received at receptors to the target sites is called second messengers. The three major classes of second messengers are cyclic nucleotides, IP3 & DAG, and calcium ions. Thus, the different second messengers in the body are cAMP, cGMP, IP3, DAG, and Ca2+.

Thus, in the given case the correct options among the following are 1, 4, and 7.

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In 1773 Benjamin Franklin, investigating the calming effect of oil on the water of a pond near London, observed that a teaspoonf
likoan [24]

Answer:

a. 2.44 nm

b. 15.33 nm²

Explanation:

a. Calculate the thickness (in nm) of the surface film

Since the volume of a teaspoon equals V = 4.93 cm³ and the area of the oil film is half an acre = 1/2 × 4046.86 m² = 2023.43 m²

The volume of the oil film, V' equals the volume of the oil in the teaspoon, V

V' = Ah where A = cross-sectional area of oil film = 2023.43 m² = 2023.43 × 10⁴ cm² and h = height of oil film

So, V' = V

Ah = V

h = V/A

= 4.93 cm³/2023.43 × 10⁴ cm²

= 0.00244 × 10⁻⁴ cm

= 2.44 × 10⁻⁷ cm

=  2.44 × 10⁻⁷ cm × 1m/100 cm

= 2.44 × 10⁻⁹ m

= 2.44 nm

b. The surface area (in nm2) occupied by an oleic acid molecule on water.

Since the height of the oil film equals the diameter of the oil molecule, and the molecule is assumed to be a sphere of radius, r. Its surface area is thus A = 4πr²

r = h/2 = 2.44 nm/2 = 1.22 nm

A = 4πr²

A = 4π(1.22 nm)²

A = 4.88π nm²

A = 15.33 nm²

7 0
2 years ago
Aerobic organisms are more active and efficient users of energy true or false
k0ka [10]
I think this is True.

Aerobic organisms are more energy-efficient than anaerobic.

~ Good luck!
6 0
3 years ago
Calculate the heat in joules "Q" needed to raise 27.0 g of water from 10.0 °C to 90.0 °C.​
Morgarella [4.7K]

Answer:

9028.8 J

Explanation:

The equation for working out the amount of thermal energy required is q = m c Δ T , where q is the amount of energy, m is the mass being heated up in grams, c is the specific heat capacity of what you're heating up in joules per gram per kelvin, and Δ T is the change in temperature in Kelvin.(Change in temperature will always give the same value,no matter Celsius or Kelvin)

mass = 27g, assuming specific heat capacity of water is 4.18 J/g*K, and the change in temperature is 90-10(=80)  , the energy needed to raise : 80 × 27 × 4.18 = 9028.8 J

5 0
2 years ago
Which statement describes heterogeneous mixtures?
artcher [175]
<span>Heterogenous mixtures are those which are seperable by physical means. These mixtures do not have uniform properties throughout the substance. For example, blood is a heterogenous mixture because it can be seperated into its components via a physical change (centrifugation). </span>
5 0
3 years ago
Read 2 more answers
True or False
notka56 [123]

Answer:

Explanation:

1.false

2.true

2.true

5 0
2 years ago
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