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Svet_ta [14]
2 years ago
9

How many moles are there in 8.50 X 1024 molecules of sodium sulfate, Na2SO3?

Chemistry
1 answer:
il63 [147K]2 years ago
3 0

Answer:

<h2>14.12 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.50 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 14.119601...

We have the final answer as

<h3>14.12 moles</h3>

Hope this helps you

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If Kp = 0.15, which statement is true of the reaction mixture before any reaction occurs?
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I found this question with the same sentence. So, I will help you using this question:

For the reaction N2O4<span>(g) ⇄ 2NO</span>2(g), a reaction mixture at a certain temperature initially contains both N2O4 and NO2 in their standard states (meaning they are gases with a pressure of 1 atm<span>).  If </span>Kp = 0.15, which statement is true of the reaction mixture before any reaction occurs?


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Kp is the equilibrium constant in term of the partial pressures of the gases.

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The reaction quotient has the same form of the equilibrium constant but using the concentrations or partial pressures at any moment.

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Since, Q = 1 and Kp = 0.15, Q > Kp and the reaction will proceed to the left.
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