Question

What is the volume of 0.200 mol of an ideal gas at 200. kPa and 400. K?

Answer 1

The ideal gas under STP is 22.4 L/mol. While the gas has a rule of P1V1/T1=P2V2/T2. So the volume under 101 kPa and 273 K is 0.2*22.4=4.48 L.

Answer 2

Answer: The volume of ideal gas is 3.32 L

Explanation:

To calculate the volume, we use the equation given by ideal gas equation:

$PV=nRT$

where,

P = pressure of the gas = 200 kPa

V = Volume of gas = ?

n = number of moles of gas = 0.200 moles

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of the gas = 400 K

Putting values in above equation, we get:

$200kPa\times V=0.200mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 400K\\\\V=\frac{0.200\times 8.31\times 400}{200}=3.32L$

Hence, the volume of ideal gas is 3.32 L