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4 years ago

14

Can someone answer this

2 answers:

elena55 [62]4 years ago

6 0

-10/3
Decimal form:-3.333333

GenaCL600 [577]4 years ago

4 0

What is the question you just said Can someone answer this what's the question

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What number has 9 tens, 7 fewer thousands than tens, the same number of hundreds as

wel

Answer:

123456678890

Step-by-step explanation:

I think this is the answer

4 0

3 years ago

What is the product of 4.5 × 10-5 and 2.4 × 10-2?

nikitadnepr [17]

4.5 • 10-5 = 40

2.4 • 10-2 = 22

4 0

3 years ago

Read 2 more answers

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

or

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

or

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

3 years ago

Mary and her brother John collect foreign coins. Mary has three times the number of coins that John has. Together they have 180

irina [24]

Mary has 135 coins and John has 45 coins.

7 0

3 years ago

Read 2 more answers

Hi , the answer I choose was wrong , what is the correct answer ? Will choose brainlest so be quick

Anastaziya [24]

Answer:

maybe its the other SAS

Step-by-step explanation:

it might be Hypotenuse Leg, but im nto 100% sure

4 0

3 years ago