Answer:
1.115 g
Explanation:
Applying,
R = R'
................... Equation 1
Where R = original sample of radon-222, R' = sample of radon-222 left after decay, n = Total time, t = half-life.
make R' the subject of the equation
R' = R/()............... Equation 2
From the question,
Given: R = 73.9 g, n = 23 days, t = 3.8 days.
Substitute these values into equation 2
R' = 73.9/(
)
R' = 73.9/
R' = 1.115 g
Niether, they are equal.
1,000 cm3 = 1000 mL
Answer:
M(AgNO3) = 169,8731 g mol
Explanation:
M(Ag) = 107,8682 g mol
M(N) = 14.0067 g mol
M(O) = 15.9994 g mol
M(AgNO3) = M(Ag) + M(N) + 3 x M(O) = 107.8682 + 14.0067 + 3 x 15.9994 =
= 169,8731 g mol
Just sum up all the respective elements' molar mass.
Answer:
47.36mL
Explanation:
Using Boyles law equation, which states that:
P1V1 = P2V2
Where;
V1 = initial volume (mL)
V2 = final volume (mL)
P1 = initial pressure (atm)
P2 = final pressure (atm)
Based on the provided information, V1 = 25.3mL, P1 = 152 kPa, V2 = ?, P2 = 0.804atm
First, we need to convert 152kPa to atm by dividing by 101
1kPa = 0.0099atm
152kPa = 1.505atm
P1V1 = P2V2
1.505 × 25.3 = 0.804 × V2
38.08 = 0.804V2
V2 = 38.08/0.804
V2 = 47.36mL
Ok boomer..................
