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vazorg [7]
3 years ago
5

Select the correct answer.

Chemistry
1 answer:
V125BC [204]3 years ago
5 0

Answer:

The mass of a marble.

Explanation:

Units of the other answers:

A: Light - Lumen (lm)

B: Volume - cm^3

D: Electric current - Ampere

You might be interested in
The radioisotope radon-222 has a half-life of 3.8 days. How much of a 73.9-g sample of radon- (3 222 would be left after approxi
Novay_Z [31]

Answer:

1.115 g

Explanation:

Applying,

R = R'2^{n/t}................... Equation 1

Where R = original sample of radon-222, R' = sample of radon-222 left after decay, n = Total time, t = half-life.

make R' the subject of the equation

R' = R/(2^{n/t})............... Equation 2

From the question,

Given: R = 73.9 g, n = 23 days, t = 3.8 days.

Substitute these values into equation 2

R' = 73.9/(2^{23/3.8})

R' = 73.9/2^{6.05}

R' = 1.115 g

6 0
3 years ago
Which is greater? 1,000ml or 1,000 cm3
pshichka [43]
Niether, they are equal.
1,000 cm3 = 1000 mL
8 0
3 years ago
Read 2 more answers
Silver (ag) has a molar mass of 107. 8682 g, nitrogen has a molar mass of 14. 0067 g, and oxygen has a molar mass of 15. 9994 g.
hjlf

Answer:

M(AgNO3) = 169,8731 g mol

Explanation:

M(Ag) = 107,8682 g mol

M(N) = 14.0067 g mol

M(O) = 15.9994 g mol

M(AgNO3) = M(Ag) + M(N) + 3 x M(O) = 107.8682 + 14.0067 + 3 x 15.9994 =

= 169,8731 g mol

Just sum up all the respective elements' molar mass.

3 0
2 years ago
.A gas occupies 25,3 mL at a pressure of 152 kPa. Find the volume if the pressure is
Strike441 [17]

Answer:

47.36mL

Explanation:

Using Boyles law equation, which states that:

P1V1 = P2V2

Where;

V1 = initial volume (mL)

V2 = final volume (mL)

P1 = initial pressure (atm)

P2 = final pressure (atm)

Based on the provided information, V1 = 25.3mL, P1 = 152 kPa, V2 = ?, P2 = 0.804atm

First, we need to convert 152kPa to atm by dividing by 101

1kPa = 0.0099atm

152kPa = 1.505atm

P1V1 = P2V2

1.505 × 25.3 = 0.804 × V2

38.08 = 0.804V2

V2 = 38.08/0.804

V2 = 47.36mL

5 0
3 years ago
Find degenerate orbitals 3dxy, 2px, 4dz2, 3dyz, 3pz,3dxz, 4sm​
IceJOKER [234]
Ok boomer..................
7 0
3 years ago
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