Question

How many protons, neutrons, and electrons are there in an atom of (a) 10B5, (b) 36Ar, (C) 85Sr38, and (d) carbon-Il?

Answer 1

Answer:

Here's what I get.

Explanation:

The isotopic symbol for an atom is

$\rm _{Z}^{M}A$

The atomic number (Z) is the number of protons (p) in the nucleus.

In a neutral atom, the number of electrons (e) equals the number of protons. n = e

The mass number (A) is the number of protons plus the number of neutrons (n).

A = p + n or

n = A - p

(a) $\rm _{5}^{10}B$

p = 5

e = 5

n = 10 - 5 = 5

(b) $\rm _{18}^{36}Ar$

p = 18

e = 18

n = 36 - 18 = 18

(c) $\rm _{38}^{85}Sr$

p = 38

e = 38

n = 85 - 38 = 47

(d)$\rm _{6}^{11}C$

p = 5

e = 6

n = 11 - 6 = 5