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bixtya [17]
3 years ago
10

How many valance electrons does oxygen have

Chemistry
1 answer:
svet-max [94.6K]3 years ago
5 0

Answer:

Six

Explanation:

Oxygen has six valence electrons in its elemental form so its formal charge is 6 – 6 = 0. Each hydrogen atom owns one electron [(2x½) = 1].

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Which expression correctly represents a balanced reduction half-reaction?
jolli1 [7]
For answering for the question, there exists four choices:
1) Na+  +  e- -------------- Na
2) Na --------Na+   +  e-
3) Cl2 +   2e-  ------------ Cl-
4) 2Cl-  ---------Cl2 +  2e-

reduction half-reaction general formula is 
oxidant + e - or +  -------- Product

so in our case the answer is 
1) Na+  +  e- -------------- Na (exactly balanced)

6 0
3 years ago
What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


4 0
3 years ago
The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker. 1.
Mars2501 [29]

C: 0.012 mol.

<h3>Explanation</h3>

Start with 0.0020 moles of iodate ions {\text{IO}_{3}}^{-}.

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How many moles of thiosulfate ions {\text{S}_2\text{O}_3}^{2-} are required?

\text{I}_2 reacts with {\text{S}_2\text{O}_3}^{2-} in the second reaction. The coefficient in front of \text{I}_2 is twice the coefficient in front of {\text{S}_2\text{O}_3}^{2-}. How many moles of {\text{S}_2\text{O}_3}^{2-} does each mole of \text{I}_2 consume? Two. 0.0060 moles of \text{I}_2 will be produced. As a result, 2 \times 0.0060 = 0.0120 moles of {\text{S}_2\text{O}_3}^{2-} will be needed.

6 0
3 years ago
Substance X has a fixed volume, and the attraction between its particles is strong. Substance Y has widely spread out particles
enot [183]
Among the choices given, the correct answer is the first option. Substance X most likely is a crystal, and substance Y most likely is a liquid. Substance X having a fixed volume describes a crystal because crystals occupy a certain volume. Substance Y is a liquid because liquids can still be compressed further in order to attain a more packed <span>structure.</span>
8 0
3 years ago
Read 2 more answers
19 The coefficients in a balanced chemical equation represent(l ) the mass ratios of the substances in the reaction(2) the mole
Andrews [41]
2. The coefficients represent to molar ratios in a balanced equation.
8 0
3 years ago
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