The amount of the nitrogen gas, N₂ molecules present is 2.68×10²² molecules
<h3>Avogadro's hypothesis </h3>
1 mole of N₂ = 6.02×10²³ molecules
<h3>How to determine the mole of N₂</h3>
We'll begin by calculating the number of mole of N₂. This can be obtained as follow:
- Mass of N₂ = 1.25 g
- Molar mass of N₂ = 28.02 g/mol
- Mole of N₂ =?
Mole = mass / molar mass
Mole of N₂ = 1.25 / 28.02
Mole of N₂ = 0.0446 mole
<h3>How to determine the molecules of N₂ present</h3>
From Avogadro's hypothesis,
1 mole of N₂ = 6.02×10²³ molecules
Therefore,
0.0446 mole N₂ = 0.0446 × 6.02×10²³
0.0446 mole N₂ = 2.68×10²² molecules
Thus, the molecules of N₂ present is 2.68×10²² molecules
Learn more about Avogadro's number:
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Answer:
2.5 mL
Explanation:
Step 1: Given data
- Concentration of the active ingredient (C): 5% v/v
- Volume of the medicine (V): 50 mL
Step 2: Calculate the amount of the active ingredient in the medicine
The concentration of the active ingredient is 5% v/v, that is, there are 5 mL of the active ingredient per 100 mL of the medicine. The volume of the active ingredient is 50 mL of the medicine is:
50 mL Med × 5 mL AI/100 mL Med = 2.5 mL AI
Answer:
The correct order of the elements, taking into account their ionic radius from highest to lowest, is:
<em>a) Cl⁻¹ > F⁻¹ > Na⁺¹ > Mg⁺²</em>
<em>b) S⁻² > O⁻² > Li⁺¹ > Be⁺²</em>
<em>c) S⁻² > Cl⁻¹ > K⁺¹ > Na⁺¹</em>
Explanation:
In ions the ionic radius is determined by the amount of electrons an element gains or loses to become an ion. The more negative an ion is, the greater its ionic radius.
As a rule, anions (negative charge) have a larger ionic radius than cations (positive charge), because the loss of electrons means a contraction of the ionic radius, while the gain of electrons means a greater radius.
To determine which ionic radius is greater in anions or cations with the same charge, it must be considered that in the periodic table the ionic radius increases from top to bottom and from right to left.
Learn more:
Ionic radius example brainly.com/question/2279609
The formula will be AI2O3