A combustion reaction involves an organic compound reacted with oxygen. The general chemical equation is as follows:
<span>
Organic Compound + Oxygen = CO2 + H2O
</span><span>To calculate the amount of C present in the original sample, we use the values given and assume that there is complete combustion that is happening.
</span><span>
7.33 g CO2 ( 1 mol CO2 / 44.01 g CO2)(1 mol C / 1 mol CO2) = 0.167 mol C
Therefore, 0.167 mol of C was originally in the sample.</span>
Volatile organic compounds can be detected by hydrogeologists in the field or labs because of the odor of the vapors emitted from the groundwater and/or soil samples.
<h3>What are volatile substances?</h3>
Volatile substances are substances which can easily vaporize or change to gaseous state.
Volatile substances can either be solids or liquids but are mostly liquids.
Example of volatile substances include ether, petrol, chocolate.
The presence of volatile substances can be detected by the gases they release which may have characteristic odors.
Therefore, volatile organic compounds can be detected by hydrogeologists in the field or labs because of the odor of the vapors emitted from the groundwater and/or soil samples.
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Answer:
x, Z, M, H, A, K, E, I, L, R, O, W
Answer: B. High precision
Explanation:
The ratio of buffer C₂H₃O₂ /HC₂H₃O₂ must you use are1:0.199 or 10:2
the ratio of buffer C₂H₃O₂ /HC₂H₃O₂ can be calculate using the Henderson-Hasselbalch Equation which relates the pH to the measure of acidity pKa. The equation is given as:
pH = pKa + log ([base]/[acid]
Where,
[base] = concentration of C₂H₃O₂in molarity or moles
[acid] = concentration of HC₂H₃O₂ in molarity or moles
For the sake of easy calculation, allow us to assume that:
[base] =1
[acid] = x
Therefore using equation 1,
5.44 = 4.74 + log (1 / x)
log [base / acid] = 0.7
1 / x = 5.0118
x = 0.199
The required ratio of buffer C₂H₃O₂ /HC₂H₃O₂ is 1:0.199 or 10:2
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