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3 years ago

14

A server worked a shift where he served 13 entrees, 8 appetizers, and 6 desserts . What percentage of his servings were

1 answer:

ryzh [129]3 years ago

6 0

Answer:

entrees 48% appetizers 30% desserts 22%

Step-by-step explanation:

18+8+6=27

13/27

8/27

6/27

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Part B: If a cross section of the rectangular pyramid is cut perpendicular to the base, passing through the top vertex, what wou

Katyanochek1 [597]

Answer:

A triangle.

Step-by-step explanation:

The plane would pass through opposite sloping faces of the pyramid and through the base; the shape formed is a triangle.

6 0

3 years ago

Boat A traveled at a speed of 15km/h for 7h a day. Boat B traveled at a speed of 25km/h for 6h a day. Find the difference travel

-BARSIC- [3]

Answer:

Boat A travels 105 km

Boat B travels 150 km

difference 45 km

8 0

2 years ago

Choose the graph which represents the solution to the inequality: <br> 3x + 8 ≥ 11

ra1l [238]

Answer:

x>1

Step-by-step explanation:

jayfeather friend me

7 0

2 years ago

I dont understand I need help

gregori [183]

Answer:

7.4825 km or 7.48 km (rounded to nearest hundredth)

Step-by-step explanation:

<u>Ranch's measurements rounded up to the nearest hundredth:</u>

1st measurement = $\sqrt{60}$ = 7.75 km

2nd measurement = $\frac{58}{8}$ = 7.25 km

3rd measurement = 7.3(recurring) = 7.33 km

4th measurement = 7 $\frac{3}{5}$ = 7.60

<u>The average of the four measurements is:</u>

(7.75 + 7.25 + 7.33 + 7.60) ÷ 4 = 7.4825 km or 7.48 km (rounded to nearest hundredth)

6 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago