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3 years ago

Solve 15 ≥ -3x or 2/5x ≥ -2. A.) {x | x ≤ -5} B.) {x | x ≥ -5} C.) {all reals}

2 answers:

6 0

$15 \geq -3x\quad|:(-3)\qquad\vee\qquad \dfrac{2}{5}x \geq -2\quad|\cdot5\\\\\\
-5 \leq x\qquad\vee\qquad 2x \geq -10\quad|:2\\\\\\
-5 \leq x\qquad\vee\qquad x \geq -5\\\\\\x\geq -5\qquad\implies\qquad\boxed{\{x | x \geq -5\}}$

Answer B.

Hunter-Best [27]3 years ago

5 0

The correct answer is C.) {all reals}

Hope this helps!!! :D

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Answer:

Diego is correct.

He has correctly divided 1 in groups of $\frac{5}{6}$ .

Step-by-step explanation:

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