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koban [17]
3 years ago
9

well, according to y0autube statistics, only a small percentage of people who watch my videos are actually subscribed, so if you

end up liking this video, consider subscribing, it's free, and you can always unsubscribe. Enjoy the video
Mathematics
2 answers:
mr_godi [17]3 years ago
6 0
Why. what and why... ahahah
Katarina [22]3 years ago
4 0
Ok.........................
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2 friends want to equally share of a bag of chocolate cookies. What
adelina 88 [10]

Answer:

is this a joke question? it is very easy. one half or 1/2

Step-by-step explanation:

8 0
3 years ago
I am doing math and in it i have to find the answer to 3^12 ans 7^9 and when i ut it in the calculator it said 2.1445561e+13 and
grin007 [14]

Answer:

40,885,048

Step-by-step explanation:

first find 3^12 and then find 7^9.

3^12 = 531,441

7^9 = 40,353,607

Add these together and you'll get 40,885,048.

Welcome! Hope this helps.

7 0
3 years ago
Read 2 more answers
X 4) Find the product of 4 x 2 3/4. 18 3/4 O 7 1/2 11 O 14​
Vadim26 [7]

9514 1404 393

Answer:

  11

Step-by-step explanation:

  4 × (2 3/4) = 4×2 + 4×(3/4) = 8 + 3 = 11

or

  4 × (2 3/4) = 4 × 11/4 = 11

5 0
3 years ago
What are the missing reasons in the two-column proof?
Nesterboy [21]

Reasons:

1. Because, MO cuts Angle PMN in two equal parts.

2.As ∠PMN is cut in to equal parts thus:

∠PMN = ∠NMO + ∠PMO, where these two parts (∠NMO, ∠PMO) are equal.

3. Both are the same, common you can say..

4. Because, MO cuts Angle PON in two equal parts.

5. As ∠PON is cut in to equal parts thus:

∠PON = ∠NOM + ∠POM, where these two parts (∠NOM , ∠POM) are equal.

6. From the above statements, we have:

= ∠NMO + ∠PMO (Proved)

= ∠NOM + ∠POM (Proved)

= MO = MO (Proved)

Thus, ∆PMO ≅ ∆NMO, by AAS rule

________________________________

As simpoool as that!

5 0
3 years ago
Samantha must include 1 English class, 1 Algebra class, and 1 Biology class in a schedule. There 3 English teachers, 4 Algebra t
astra-53 [7]

To solve this problem, we make use of the formula of combination.

nCr = n! / r! (n – r)!

where n is the total number of subject teachers and r is the number of subjects r = 1

 

For the English class n = 3

3C1 = 3! / 1! (3 – 1)! = 3

 

For the Algebra class n = 4

4C1 = 4! / 1! (4 – 1)! = 4

 

 

For the Biology class n = 2

2C1 = 2! / 1! (2 – 1)! = 2

 

The total number of different schedules would be the product of the three combinations:

total combinations possible = 3 * 4 * 2

total combinations possible = 24

4 0
4 years ago
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