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3 years ago

Which equation is equivalent to 5= 4/3 (6y +9)?

Mathematics

1 answer:

vekshin13 years ago

8 0

Answer:

option C

Step-by-step explanation:

$5 = \frac{4}{3}(6y + 9)\\\\5 = \frac{4\times6y}{3} +\frac{4 \times 9}{3}\\\\5= 8y + 12$

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What is the median of 40,33,37,54,41,34,27,39,35

Sauron [17]

Answer:

It's 37

Step-by-step explanation:

The given data set is ;

40,33,37,54,41,34,27,39,35

We arrange the data set in ascending order to obtain;

{27,33,34,35,37,39,40,41,54}

The median is the middle number {37}

8 0

3 years ago

Which is bigger 5/12 or 7/24

7nadin3 [17]

I would say 7/24 because when you multiply it you should be able to get a large number.

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Write a word problem using the whole number 4 and the fraction 3/8' then solve the problem.

cricket20 [7]

There are 4 cookies. James eat 3/8 of the cookies. How many cookies are left?

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3 years ago

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A home mortgage is usually borrowed for how long

mash [69]

The traditional home mortgage is usually borrowed for 30 years.

6 0

3 years ago

Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i

bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

$\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx$

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1) with respective to 'x'

$\frac{dx}{dt} = 1+cost$

differentiating equation (2) with respective to 'y'

$\frac{dy}{dt} = -sint$

The length of curve is

$\int\limits^\pi_\pi {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt$

$\int\limits^\pi_\pi \, {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt$

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

$\int\limits^\pi_\pi \, {\sqrt{(2+2cost } } \, dt$

$\sqrt{2} \int\limits^\pi_\pi \, {\sqrt{(1+1cost } } \, dt$

again using formula, 1+cost = 2cos^2(t/2)

$\sqrt{2} \int\limits^\pi _\pi {\sqrt{2cos^2\frac{t}{2} } } \, dt$

Taking common $\sqrt{2}$ we get ,

$\sqrt{2}\sqrt{2} \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt$

$2(\int\limits^\pi _\pi {cos\frac{t}{2} } \, dt$

$2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }$

length of curve = $4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))$

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

7 0

3 years ago