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Brums [2.3K]
3 years ago
15

8579 = 20.5% of x What is x

Mathematics
1 answer:
frutty [35]3 years ago
6 0

Hope attachment helps (✿^‿^)

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Why negative integers are not in solution set
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Negative numbers aren't in a solution set because in equations and inequalities you have to multiply and divide and a positive number divided by a negative number will be a negative number. Positive divided by positive will be positive. Negative divided by negative will be positive. So that's why negative numbers aren't a solution to any set or equation. 

hope this helps
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Graph the function f(x) = 2 sqrt x+3.
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Step-by-step explanation:

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Find the approximate length of the track, including the straight and circular sections
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Step-by-step explanation:

6 0
3 years ago
Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ
Deffense [45]

Answer:

\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}

Step-by-step explanation:

Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}

\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16

\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i

6 0
3 years ago
Read 2 more answers
Evaluate 4+(7-5) <br><br>please help,y'all lol ​
natali 33 [55]
It should be 6 I believe
7 0
2 years ago
Read 2 more answers
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