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andreyandreev [35.5K]
3 years ago
5

Because the triple beam balance is zeroed before it is put into use, it measures

Chemistry
1 answer:
AURORKA [14]3 years ago
5 0
Answer b weight....
Hope this helps
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Explain why you cannot just take away a proton to make a halogen negative.​
Ilia_Sergeevich [38]

The force that holds protons and neutrons together is too strong to overcome.

<h3>Explanation</h3>

Consider the location of the particles in an atom.

  • Electrons are found outside the nucleus.
  • Protons and neutrons are found within the nucleus.

Protons carry positive charges and repel each other. The nucleus will break apart without the strong force that holds the protons and neutrons together. This force is much stronger than the attraction between the nucleus and the electrons. X-rays are energetic enough for removing electrons from an atom. However, you'll need a collider to remove protons from a stable nucleus. You could well have ionized the atom with all that energy.

Also, changing the number of protons per nucleus will convert the halogen atom to an atom of a different element. Rather than making the halogen negative, removing a proton will convert the halogen atom to the negative ion of a different element.

6 0
3 years ago
Stainless steel is an alloy of iron, chromium, nickel, and manganese metals. If a 2.000 g sample contains 10.0% nickel, what is
AfilCa [17]

Answer:

200 g

Explanation:

Stainless steel is an alloy of iron, chromium, nickel, and manganese metals. A 2.000 g sample contains 10.0% nickel (mass percent), that is, there are 10.0 g of nickel every 100 g of the sample. The mass of nickel in the sample is:

2.000 g sample × (10.0 g Nickel/100 g sample) = 200 g Nickel

There are 200 grams of Nickel in the 2.000 g-sample.

7 0
3 years ago
My professor gave me two questions to solve using the Van Der Waals Equation. She told us to solve for P and the second one we h
Fed [463]

Answer:

P=atm

b=\frac{L}{mol}

Explanation:

The problem give you the Van Der Waals equation:

(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT

First we are going to solve for P:

(P+\frac{n^{2}a}{V^{2}})=\frac{nRT}{(V-nb)}

P=\frac{nRT}{(V-nb)}-\frac{n^{2}a}{v^{2}}

Then you should know all the units of each term of the equation, that is:

P=atm

n=mol

R=\frac{L.atm}{mol.K}

a=atm\frac{L^{2}}{mol^{2}}

b=\frac{L}{mol}

T=K

V=L

where atm=atmosphere, L=litters, K=kelvin

Now, you should replace the units in the equation for each value:

P=\frac{(mol)(\frac{L.atm}{mol.K})(K)}{L-(mol)(\frac{L}{mol})}-\frac{(mol^{2})(\frac{atm.L^{2}}{mol^{2}})}{L^{2}}

Then you should multiply and eliminate the same units which they are dividing each other (Please see the photo below), so you have:

P=\frac{L.atm}{L-L}-atm

Then operate the fraction subtraction:

P=P=\frac{L.atm-L.atm}{L}

P=\frac{L.atm}{L}

And finally you can find the answer:

P=atm

Now solving for b:

(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT

(V-nb)=\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}

nb=V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}

b=\frac{V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}}{n}

Replacing units:

b=\frac{L-\frac{(mol).(\frac{L.atm}{mol.K}).K}{(atm+\frac{mol^{2}.\frac{atm.L^{2}}{mol^{2}}}{L^{2}})}}{mol}

Multiplying and dividing units,(please see the second photo below), we have:

b=\frac{L-\frac{L.atm}{atm}}{mol}

b=\frac{L-L}{mol}

b=\frac{L}{mol}

7 0
3 years ago
Please help me..!!!!!!!!!!!!!
Viefleur [7K]

Answer:

The answer you selected is correct (A)have

Explanation:

Red blood cells  one goal which is to carry oxygen throughtout your body.. without it you would die to lack of oxygen.

5 0
3 years ago
Question 2 (1 point)
Alexxandr [17]

Answer:

a mole have have wrong becouse i understand

4 0
3 years ago
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