Answer:
10.32 moles of ammonia NH₃
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 6.21×10²⁴ molecules
Number of mole of NH₃ =?
The number of mole of NH₃ can be obtained as follow:
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
6.21×10²⁴ molecules = 6.21×10²⁴ / 6.02×10²³
6.21×10²⁴ molecules = 10.32 moles
Thus, 6.21×10²⁴ molecules contains 10.32 moles of ammonia NH₃
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The answer is 59.01 g
If a 100-gram sample of NaCl consists of 39.34 g of sodium, a 150-gram sample of NaCl will consist x g of sodium:
100 g : 39.34 g = 150 g : x
x = 39.34 g * 150 g : 100 g
x = 59.01 g
