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kirill [66]
3 years ago
12

Please help will make brainliest ​

Mathematics
1 answer:
Dima020 [189]3 years ago
3 0
The answer would be

B.
C.
E.
F.
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Solve the equation Round to the nearest hundredth If necessary.
ANEK [815]
X-5=square root of 51

Add 5

X=5+7.14. And x= 5- 7.14

12.14. And -2.14.

D
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3 years ago
-14.25 + -3.78 - (-5.78) - 3.4 A) -19.65 B) -15.65 C) 1.29 D) 27.21
lutik1710 [3]
The answer is B. -15.65
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3 years ago
Solve 1.8c = 7.5 for c.
igor_vitrenko [27]
1.8c=7.5 \\\\ c=\frac{7.5}{1.8} \\\\ c=\frac{5\frac{5}{10}}{1\frac{8}{10}}=\frac{5\frac{1}{2}}{1\frac{4}{5}} \\\\ c=\frac{\frac{11}{2}}{\frac{9}{4}}= \frac{11}{2}*\frac{4}{9} \\\\ \boxed{c=\frac{22}{9}}
8 0
4 years ago
Read 2 more answers
Please help explanation if possible
Zielflug [23.3K]

Answer:

length = 48 feet , width = 32 feet

Step-by-step explanation:

Using

2W + 2L = 160 with W = L - 16 , then

2(L - 16) + 2L = 160 ← distribute and simplify left side

2L - 32 + 2L = 160

4L - 32 = 160 ( add 32 to both sides )

4L = 192 ( divide both sides by 4 )

L = 48

Substitute L = 48 into W = L - 16

W = 48 - 16 = 32

Thus length = 48 feet and width = 32 feet

3 0
3 years ago
Read 2 more answers
Ocean tides can be modeled by a sinusoidal function. Suppose that there is a low and high tide every 12 hours, and that high tid
USPshnik [31]

Answer:

(a)y=5sin(\frac{\pi}{6}(x+2))+5

(b) 7.5ft above the low tide.

Step-by-step explanation:

(a) To find the function that computes the height of the tide, you need to select the form of the sinusoidal function. For example, use the form:

y=Asin(B(x-C))+D

Where A is the amplitude, B the frequency, C the phase shift and D the vertical shift.

The  amplitude is half the distance between the highest and the lowest tide:

A=10/2=5ft

The frequency is related to the period T by:

B=\frac{2\pi}{T}

The period is 12 hours, then

B=\frac{2\pi}{12}=\frac{\pi}{6}

The high tide is at 1:00 a.m. and 1:00 p.m. , this is the moment when sin(B(x-C))=1, if sin(\frac{\pi}{2})=1 then B(x-C) must be equal to \frac{\pi}{2} when x=1:

B(x-C)=\frac{\pi}{2}\\\frac{\pi}{6}(1-C)=\frac{\pi}{2}\\\frac{1}{6}(1-C)=\frac{1}{2}\\(1-C)=\frac{6}{2}\\-C=3-1\\C=-2

The vertical shift is the sum of the lowest value, the height of the low tide (lt) and the amplitude:

D=5+lt

The function is:

y=5sin(\frac{\pi}{6} (x+2))+5+lt

Because the function must be the height above low tide height, subtract this heigh from the function:

y=5sin(\frac{\pi}{6} (x+2))+5+lt-lt

y=5sin(\frac{\pi}{6} (x+2))+5

(b) Use x=11 in the function

y=5sin(\frac{\pi}{6} (11+2))+5=2.5+5=7.5ft above the low tide.

3 0
3 years ago
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