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belka [17]
3 years ago
8

What is local area network​

Computers and Technology
2 answers:
weqwewe [10]3 years ago
6 0

Answer and Explanation:

A local area network is a computer network that interconnects computers within a limited area such as a residence, school, laboratory, university campus or office building. The function of Local Area Networks is to link computers together and provide shared access to printers, files, and other services..

otez555 [7]3 years ago
3 0

Explanation:

local area network is a computer network that interconnects computers within a limited area such as a residence, school, laboratory, university campus or office building. By contrast, a wide area network not only covers a larger geographic distance, but also generally involves leased telecommunication circuits.

<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em>

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3.A ball is thrown into the air with an initial velocity of 15 m/s. a.How long does it take the ball to reach maximum height?b.W
ehidna [41]

Answer:  a) = 1.5 sec.  b= 11.5 m. c=0  d= 1.5 sec.

Explanation:

a) Once thrown into the air , the only influence on the ball is gravity, so, we can conclude that the acceleration acting on the ball is the one due to gravity, i.e., g= 9.8 m/sec².

Applying the definition of acceleration, we can write the following equation:

a= (vf-vo) / t   ⇒ g = vf-vo / t. (1)

Now, when the ball reaches to his maximum height, it stops momentarily, and then starts to fall, so for this height, we can write vf=0.

Replacing  in (1), and solving for t, we get:

t = (0 -vo) / g = -15 m/s/ - 9.8 m/sec² (Taking upward as positive  direction)

a) t= 1.5 sec.

Replacing this value in the kinematic equation for displacement, when vo=15 m/s, we get:

hmax: 15 m/sec . 1.5 sec -1/2. 9.8 m/sec². (1.5 sec) ² (2)

b) hmax= 11.5 m

c) vf= 0 (as explained above)

Finally, in order to know how long the ball takes to return to its initial height, we know that for the falling part of the trajectory, vo=0, so we can write the equation for displacement as follows:

h=-hmax (because it returns to the same starting point)= 1/2 gt²=-11.5 m

Solving for t, we get:

d) t=1.5 sec.

It can be seen that the time used in going up, it is the same for going down, to travel the same distance.

This result is completely general and applies to any free fall problem.

3 0
3 years ago
A detective agency is looking to bust an arms sale. According to available intelligence, the sale is likely to happen in one of
Paha777 [63]

Answer:

Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}

H(X)=5.4224 bits per symb

H(X|Y="not C")=0.54902 bits per symb

Explanation:

P(B)=2P(C)

P(A)=2P(B)

But

P(A)+P(B)+P(C)=1

4P(C)+2P(C)+P(C)=1

P(C)=1/7

Then

P(A)=4/7

P(B)=2/7

Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}

iii

If X={A,B,C}

and P(Xi)={4/7,2/7,1/7}

where  Id =logarithm to base  2

Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}

=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}

=5.4224 bits  per symb

if P(C)  =0

P(A)=2P(B)

P(B)=1/3

P(A)=2/3

H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)

=0.54902 bits per symb

4 0
3 years ago
Assume that word is a variable of type String that has been assigned a value. Assume furthermore that this value always contains
Valentin [98]

Answer:

   String word = "George slew the dragon";

   

   int pos = word.indexOf("dr");    

   String drWord = word.substring(pos, pos+4);

   

   System.out.println(drWord);

Explanation:

Assuming dr is always there, we don't have to check the validity of 'pos'. Normally, you would!

5 0
3 years ago
Read 2 more answers
6. Which of the following is malware? (1 point)
marusya05 [52]
Software to damage computers
5 0
3 years ago
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When you use the mvc pattern for a java web application, you often add ________________________ to the request object before you
aivan3 [116]
Hi,

JVM - Java Virtual Machine

Hope this helps.
r3t40
6 0
3 years ago
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