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astra-53 [7]
3 years ago
5

Consider the problem: After charging for 1/3 of an hour, a phone is at 2/5 of its full power. How long will it take the phone to

charge completely? Decide whether each equation can represent the situation.

Mathematics
2 answers:
prisoha [69]3 years ago
5 0

Answer:

Equation 2

is the answer

Step-by-step explanation:

Alinara [238K]3 years ago
4 0

To calculate the time for a full charge, you would divide the time already charged by the amount of charge:

1/3 / 2/5 = 1/3 x 5/2 = 5/6 of an hour for full charge.

You could use 2 and 4 to find the time.

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A map has a scale of 4cm. to 12 km. what distance does 16 cm represent
Assoli18 [71]
16/4=4
4*12=48km
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4 0
3 years ago
A system of linear equations is shown below where
Brums [2.3K]

Answer:

543

Step-by-step explanation:

8 0
3 years ago
What is the value of the expression shown below if x = 3, y = 6, and z =<br> 4?<br> x² + 3yz
Karo-lina-s [1.5K]

Answer:

81

Step-by-step explanation:

The initial expression:

x^2+3yz

Identify your values:

x=3\\y=6\\z=4

Substitute:

(3)^2+3(6)(4)

Following PEMDAS, nearly everything is in parentheses, so move to exponents:

9+3(6)(4)

Multiply 6 and 4:

9+3(24)

Multiply 3 and 24:

9+72

Simplify:

81

5 0
3 years ago
Please Help me Find NM using Secant
kondaur [170]

Answer:

NM = 15

Step-by-step explanation:

There is a property of secants and tangents to a circle where:

The square of the tangent length is equal the length of the external segment of the secant times the whole secant length.

Therefore, in our question, we have that:

NM^2 = ML * MK

The values of NM, ML and MK are:

NM = x + 3

ML = x - 3

MK = ML + LK = x - 3 + 16 = x + 13

So we have:

(x+3)^2 = (x - 3)(x + 13)

x^2 + 6x + 9 = x^2 + 10x - 39

6x + 9 = 10x - 39

4x = 48

x = 12

So the length of NM is:

NM = x + 3 = 12 + 3 = 15

3 0
3 years ago
Use the distributive property to rewrite this expression.<br> 4(y + 6)
inn [45]

Answer:

4y + 24

Step-by-step explanation:

4(y + 6)
(4 * y) + (4 * 6)
(4y) + (24)
4y + 24

8 0
2 years ago
Read 2 more answers
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